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The linear function y = (M + 4) X-5 + 2m, when___ When x increases, y increases___ The image passes through the origin___ The image does not pass through the first quadrant
When ∵ k > 0, y increases with the increase of X, ∵ m + 4 > 0, i.e. m > 4; ∵ B = 0, the image of the first-order function passes through the origin, ∵ 5 + 2m = 0, i.e. M = 52; ∵ K < 0 and B < 0, the image does not pass through the first quadrant, ∵ m + 4 < 0, and - 5 + 2m < 0, i.e. m < - 4, m < 52, then M < - 4
Given that the image of the first order function y = (2-m) x + 2m-5 does not pass through the first quadrant, the value range of M is obtained
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Because the image of the linear function y = (2-m) x + 2m-5 does not pass through the first quadrant
So 2-m
To make the image of primary function y = 3mx + 5m-4 pass through the origin, then M = (?) to make the image of primary function y = (2m-1) x + 6m-5 not pass through the second quadrant, then the value range of M is?
In order to make the image of the first-order function y = 3mx + 5m-4 cross the origin, then M = (4 / 5)
If the image of the first-order function y = (2m-1) x + 6m-5 does not pass through the second quadrant, then the value range of M is?
2m-1≥0;
6m-5≤0;
∴1/2≤m≤5/6;
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Negative two and one-fifth × (one-third to one-half) × five fifths of eleven △ (- 0.75)
Negative two and one-fifth × (one-third to one-half) × five fifths of eleven △ (- 0.75)
=-（11/5）×(2/6-3/6)×(5/11)×(-4/3)
=(-1/6)×(4/3)
=-2/9;
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It is known that | x + 1 / 5 | + | Y - 1 / 2 | + | Z + 3 has 1 / 3 | = 0
Find the value of (x-1) (Y-2) (Z + 5)
|X + 1 / 5 | + | Y - 1 / 2 | + | Z + 3 has 1 / 3 | = 0x + 1 / 5 = 0x = - 1 / 5y-1 / 2 = 0y = 1 / 2Z + 3 and 1 / 3 = 0z = - 3 and 1 / 3 (x-1) (Y-2) (Z + 5) = (- 1 / 5-1) (1 / 2-2) (- 3 and 1 / 3 + 5) = (- 6 / 5) x (- 3 / 2) x (5 / 3) = 3. If you don't understand this question, please click the bottom right
How to do 18 questions on page 75 of Volume 1 of Volume 1 of Volume 7?
Tom is running with a dog at the speed of 3 meters per second. He finds a bone 33 meters in front of him. The dog rushes forward at the speed of 6 meters per second. Tom continues to move forward at the original speed. When the dog arrives at the destination, it takes 1 second to pick up the bone, then quickly turns around and returns to Tom at the speed of 6 meters per second. (1) If it takes T seconds for the dog to leave Tom and rejoin with Tom, use the algebraic expression containing T to express the distance the dog has traveled in this period of time; (2) how long does it take for the dog to leave Tom and rejoin with Tom?
(1) 6 (t-1) = 6t-6 (m)
(2) 3T + 6 (t-6.5) = 33, t = 8
How to calculate 2.8/half * half / 0.7?
2.8/half * half / 0.7
=2.8÷0.7
=4;
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How to calculate two and one third - 0.2 × (0.5 + one third) × one half?
Two and one third - 0.2 × (0.5 + one third) × one half = 2 + 1 / 3-1 / 5 × (0.5 + 1 / 3) × 2 = 2 + 1 / 3-2 / 5 × (1 / 2 + 1 / 3) = 2 + 1 / 3-2 / 5 × 5 / 6 = 2 + 1 / 3-1 / 3 = 2
The mixed operation of rational numbers_____ Simplify the operation, can be used first____ Calculate
If the mixed operation of rational numbers can be used to simplify the operation, the equation can be solved first
4 △ 1 / 2 × (5 / 8-1 / 4) simple calculation!
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=8×（5/8-1/4）=8×5/8-8×1/4=5-2=3
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