If the power of 4m · the power of 8m - 1 divided by the power of 2m = 512, the value of M can be obtained

If the power of 4m · the power of 8m - 1 divided by the power of 2m = 512, the value of M can be obtained

A:
4m power · 8m power - 1 power divided by 2m power = 512
(4^m)×[8^(m-1)]÷(2^m)=512
[2^(2m)]×[2^(3m-3)]÷(2^m)=512
2^(2m+3m-3-m)=2^9
2^(4m-3)=2^9
4m-3=9
m=3

2 / 3 + 3 / 4 △ (1 / 2-2 / 5)

2/3+3/4÷(1/2-2/5)
=2/3+3/4÷1/10
=2/3+3/4*10
=2/3+15/2
=49/6

The printing factory has to print 4800 test papers. It took half an hour to print and completed two fifths of the total number. According to this calculation, the total number of printing tasks has been completed
How long? Formulate and explain each step

1 / 2 / 2 / 5 = 5 / 4 (hours)

The ratio of X to 2 / 3 is equal to 1.6 to 2.8

x：2/3 =1.6:2.8
x=1.6×2/3÷2.8
X = 8 / 21

Five eighths times twenty-five sixteenth and 21 times nine thirty-five times six,

Five eighths multiplied by twenty-five sixteenth
=(8 times 16) of (5 times 25)
=125 out of 128
21 times nine out of 35 times six
=35 (21 times 9 times 6)
=162 out of 5
=32 and two fifths

25 × 104 simple operation (the first answer is adopted)

25×104
＝25x(100+4)
=25x100+25x4
=2500+100
=2600

The calculation is simple by using the law of operation
(68*25)*4 72*162+28*162 125*64
Just another vertical calculation to test you
178*46 408*35 380*23

(68*25)*4
=68×（25×4）
=68×100
=6800
72*162+28*162
=（72+28）×162
=100×162
=16200
125*64
=125×（8×8）
=（125×8）×8
=1000×8
=8000

Judgment question: is it right or wrong to use the law of operation to calculate?

Generally speaking, the operation law can simplify the calculation, but it is obviously more troublesome sometimes

Simple calculation by finding the law
7/6 + 13/12 + 21/21 + 31/30 + 43/42 + 57/56 + 73/72 + 91/90
How simple?

7/6 + 13/12 + 21/21 + 31/30 + 43/42 + 57/56 + 73/72 + 91/90 =[(2*3+1)/2*3]+[(3*4+1)/3*4]+[(4*5+1)/4*5]+[(5*6+1)/5*6]+[(6*7+1)/6*7]+...=1+1/2*3+1+1/3*4...=8+1/2*3+1/3*4+1/4*5+1/5*6+1/6*7+...=8+1/2-1/3+...

If a, B and C are all greater than 0, and 5 out of 7 A = 7 out of 5 B = 1 out of 2 C, try to judge the size relationship of a, B and C
emergency

If a, B and C are all greater than 0, and 5 out of 7 A = 7 out of 5 B = 1 out of 2 C, try to judge the size relationship of a, B and C
Let 5a of 7 = 7b of 5 = 1C of 2 = 1;
Then a = 7 / 5;
b=5/7;
c=2;
∴c＞a＞b;
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