Paint the six sides of a cube shaped building block, and then saw them into 64 small blocks of the same size. How many pieces are there on one side, two sides, three sides and none?

Paint the six sides of a cube shaped building block, and then saw them into 64 small blocks of the same size. How many pieces are there on one side, two sides, three sides and none?

One side is the cube which is not adjacent to the edge on each side. Sawing 64 pieces is equivalent to sawing four cubes on each side. Therefore, there are 2 × 2 = 4 cubes in the middle of each side which are not adjacent to the edge, and the total number of six sides is 4 × 6 = 24
On both sides are cubes which belong to edges but not vertices. Each edge has 2 edges, a total of 12 edges, a total of 2 × 12 = 24
On both sides is a cube that belongs to the vertex of a large cube. It has eight vertices, so there are eight

A cube with red paint on its surface is sawn into 125 small blocks of the same size, and the small blocks with different paint surfaces are calculated

There were 8 pieces with paint on three sides, 36 pieces with paint on two sides, 54 pieces with paint on one side and 27 pieces without paint on one side

First grade math / / / / / saw a cube into 64 small building blocks of the same size. How many small building blocks are there with three sides painted, two years painted and one side painted?

There are 8 painted on three sides, 24 painted on two sides, 24 painted on one side and 8 unpainted

Factorization AB (C & # 178; - D & # 178;) + CD (A & # 178; - B & # 178;)

The original formula = ABC & # 178; - abd & # 178; + A & # 178; cd-b & # 178; CD
=(abc²+a²cd)-(abd²+b²cd)
=ac(bc+ad)-bd(bc+ad)
=(bc+ad)(ac-bd)

Factorization: (C & # 178; - B & # 178; + D & # 178; - A & # 178;) &# 178; - 4 (AB CD) &# 178;

（c²-b²+d²-a²）²-4（ab-cd）²
=[（c²-b²+d²-a²）+2（ab-cd）][（c²-b²+d²-a²）-2（ab-cd）]
=[(c²-2cd+d²)-(a²-2ab+b²)][(c²+2cd+d²)-(a²+2ab+b²)]
=[(c-d)²-(a-b)²][(c+d)²-(a+b)²]
=(c-d+a-b)(c-d-a+b)(c+d+a+b)(c+d-a-b)

Factorization AB (C & # 178; + D & # 178;) + CD (A & # 178; + B & # 178;)

Expansion = ABC2 + abd2 + a2cd + b2cd
Recombination = (ABC2 + a2cd) + (abd2 + b2cd)
Extract the common factor = AC (BC + AD) + BD (AD + BC)
Then extract the common factor = (BC + AD) (AC + BD)

Factorization of AB (C & # 178; - D & # 178;) - (A & # 178; - B & # 178;) CD

The original formula = ABC & # 178; - abd & # 178; - A & # 178; CD + B & # 178; CD
＝ac﹙bc－ad﹚＋bd﹙bc－ad﹚
＝﹙bc－ad﹚﹙ac＋bd﹚.

Several factorizations of elementary one
1、 a²+a-b²-b
2、 10a(a-b)-8b(b-a)
3、 x²+4x+3
4、 p²-5p-36
5、 81x^4-72x²y²+16y^4
6、 (a²+b²)²-4a²b²
7、 x^3-4x²y+4xy²
8、 ab²-2a²b+a^3
9、 x²+2x+1-y²

The first day of junior high school
Factorization:
x^2-y^2+x^3-y^3
x^2-y^2-z^2-2yz-2x+1

x^2-y^2+x^3-y^3
=(x+y)(x-y)+(x-y)(x^2+xy+y^2)
=(x+y)(x^2+xy+y^2+x+y)
x^2-y^2-z^2-2yz-2x+1
=(x^2-2x+1)-(y^2+2yz+z^2)
=(x-1)^2-(y+z)^2
=(x-1+y+z)(x-1-y-z)

Some questions in the Handbook of English Evaluation for junior one
Fill in the blanks according to the initials-
1.His parernts are b______ tall.He plays basketball f______ Houst Rockets in teh USA.Now more and more Americans begin to like him.They think he plays very w______ .
2.He usually likes w______ sports clothes.When he has time,he e______ playing computer games and listening to music.He loves animals.He likes dogs b______ .His favourite food is sausage and tomatoes.

both for well wear ever better