204x out of 3 minus 8x out of 3 equals 200

204x out of 3 minus 8x out of 3 equals 200

204x/3-8x²/3=200
8x²-204x+600=0
2x²-51x+150=0
Discriminant = 51 × 51-8 × 150 = 1401
x=(51±√1401)/4
C reference

The sum of the first n terms of the arithmetic sequence an and BN is Sn and TN respectively, and Sn / TN = 3n-1 / 2n + 1, so the value of A3 / A4 can be obtained

Factorization of 4m ^ 3n-16mn ^ 3

4m^3n-16mn^3 =4mn(m^2-4n^2) =4mn(m-2n)(m+2n)

Decomposition factor: - 4m ^ 2n ^ 3 + 12m ^ 3N ^ 2-2mn

－4m^2n^3+12m^3n^2-2mn
=2mn（6m²n-2mn²-1）
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Factorization of 12 x ^ (2n + 1) y ^ (M + 1) - 20x ^ (n + 1) y ^ (2m + 3)

12 x^(2n+1)y^(m+1)- 20x^(n+1)y^ (2m+3)
=4x^(n+1)y^(m+1)(3x^n- 5y^ (m+2))

Factorization of 4m & # 178; - 4m + 16

=4(m²-m+4)

（m^2+4m）^2+8（m^2+4m）+16
2.（3a-5b）^2-（5a-3b〉^2 3.4a^2-16a^4 4.4a^2-（a^2+1）^2 5.9x^2-y^2-6x+1

Factorization of mathematics in grade one
1.（m^2+4m）^2+8（m^2+4m）+16
The results are as follows
==[(m^2+4m)+4]^2
==(m^2+4m+4)^2
==(m+2)^4
2.（3a-5b）^2-（5a-3b〉^2
The results are as follows
==[(3a-5b)+(5a-3b)]*[(3a-5b)-(5a-3b)]
==(8a-8b)*(-2a-2b)
==-16(a-b)*(a+b)
3.4a^2-16a^4
The results are as follows
==4a^2(1-4a^2)
==4a^2(1+2a)(1-2a)
4.4a^2-（a^2+1）^2
The results are as follows
==[2a+（a^2+1）]*[ 2a-（a^2+1） ]
==(2a+a^2+1）*(2a-a^2-1）
==-(a+1)^2(a-1)^2
5.9x^2-y^2-6x+1
The results are as follows
== (9x^2-6x+1)-y^2
==(3x-1)^2-y^2
==(3x-1+y)(3x-1-y)

Factorization of x ^ 3 + 3x ^ 2 + 7x + 5

x^3+3x^2+7x+5
=(x^3+x^2)+(2x^2+7x+5)
=x^2(x+1)(2x+5)(x+1)
=(x+1)(x^2+2x+5)

It is known that the image of the first-order function y + 2x-k intersects the image of the inverse scale function y = K + 5 / x, and the abscissa of one of the intersections is - 3 / 2. The expressions of the two functions are obtained

The abscissa of the intersection is - 3 / 2
Y = 2x-k = - 3-K = K-10 / 3, k = 1 / 6
therefore
y=2x-1/6
y=1/6+5/x
The main idea of this problem is that the intersection passes through two images at the same time

Where y is not a function of X
A. Y = 3 / 2 x b.y = 1 / X C.Y = x & # 178; D.Y = ± x
2 write out a functional relation of the image passing through the point (1, - 1)

1D2 is correct. The reason why 1D is not a function of X is that the same X can correspond to two or more Y values, and none of them is a function