If a = 3 ^ 4, B = 4 ^ 3, use the algebraic formula containing a and B to express 12 ^ 12

If a = 3 ^ 4, B = 4 ^ 3, use the algebraic formula containing a and B to express 12 ^ 12

12^12=3^12×4^12=(3^4)^3×(4^3)^4=a^3×b^4

If a = 243, B = 125, try to express 15 ^ 15 with algebraic formula containing a and B

a=243=3^5,b=125=5^3
15^15=(3*5)^15=3^15*5^15=(3^5)^3*(5^3)^5=a^3*b^5
I hope it will be helpful to your study,

It is known that a = LG (1 + 17), B = LG (1 + 149), and the formula containing a and B is used to express lg1.4

A = LG (1 + 17) = lg87 = lg8-lg7 = 3lg2-lg7, B = LG (1 + 149) = lg5049 = lg50-lg49 = lg1002-lg49 = lg100-lg2-2lg7 = 2-lg2-2lg7, because 3lg2-lg7 = a, 2-lg2-2lg7 = B, the two equations are combined to get LG2 = 17 (2a-b + 2), lg7 = 17 (6-a-3b), lg1.4 = lg1410 = lg14-1 = LG2 + lg7-1 = 17 (2a-b + 2) + 17 (6-a-3b) - 1 = a − 4B + 17

Let LG (1-1 / 9) = a, LG (1-1 / 81) = B. try to express LG2 and Lg3 with algebraic expressions containing a and B

LG (1-1 / 9) = LG8 / 9 = LG2 ^ 3-lg3 ^ 2 = 3 * lg2-2 * Lg3 = alg (1-1 / 81) = LG80 / 81 = lg5 * 2 ^ 4-lg3 ^ 4 = 4 * lg2-4 * Lg3 + lg5 = 4 * lg2-4 * Lg3 + LG10 / 2 = 4 * lg2-4 * Lg3 + 1-lg2 = 3 * lg2-4 * Lg3 + 1 = b

Given that y = 2 ^ m + 1, x = 3 + 16 ^ m, use the algebraic expression of y to express X

y=2^m+1,
2^m=y-1
m=log2[y-1]
Take m into the expression of X
x=3+16^m
=3+16^{l0g2[y-1]}
=3+2^{4log2[y-1]}
=3+2^{log2[y-1]^4}
=3+(y-1)^4
So x = (Y-1) ^ 4 + 3

Given that x = 2m + 1, y = 3 + 4m, the algebraic expression containing x is used to express y, then y=______ ．

∵ 4m = 22m = (2m) 2, x = 2m + 1, ∵ 2m = X-1, ∵ y = 3 + 4m, ∵ y = (x-1) 2 + 3, i.e. y = x2-2x + 4

Given that x = 2 ^ m + 1, y = 5 + 4 ^ m, try to express y with an algebraic formula containing X

x=2^m+1
∴2^m=x-1
y=5+4^m
=5+(2²﹚^m
=5+(2^m)²
=5+x-1
=x+4
That is y = x + 4

Algebraic expression: any integer; any odd number; any even number
The letter is not limited

n
2N-1 (n is a positive integer)
2n (n is a positive integer)

Given that n is the equation x & # 178; - 2x-2 = 0, find the value of the algebraic formula (n & # 178; - 2n) (n-2 / N + 1)

Given that n is the solution of the equation x & # 178; - 2x-2 = 0, find the value of the algebraic formula (n & # 178; - 2n) (n-2 / N + 1)?
x²-2x-2=0,
n²-2n-2=0,n²-2n=2;
N & # 178; - 2n-2 = 0, both sides are the same as △ n (∵ n ≠ 0), n-2-2 / N = 0; n-2 / N = 2, n-2 / N + 1 = 3
(n²-2n)(n-2/n+1)=2/3;

9-1 = 8 16-4 = 12 25-9 = 16... What's the rule that n is greater than 1 or = 1? Use n to express the algebraic expression

(n+2)²-n²=4(n+1)