The base and area of a triangle and a parallelogram are equal respectively. The height of the triangle is 5cm, and the height of the parallelogram is 5cm______ ．

The base and area of a triangle and a parallelogram are equal respectively. The height of the triangle is 5cm, and the height of the parallelogram is 5cm______ ．

The area of parallelogram is: S = ah1, the area of triangle is: S = ah2 ／ 2, so ah1 = ah2 ／ 2, H1 = H2 ／ 2, the height of parallelogram is: 5 ／ 2 = 2.5 (CM), answer: the height of parallelogram is 2.5 cm, so the answer is: 2.5 cm

As shown in the picture, a rectangular grassland is 16 meters long and 10 meters wide. There are two paths in the middle. One is a rectangle and the other is a parallelogram. The area of the grassland is______ Square meters

(16-2) × (10-2) = 14 × 8 = 112 (square meters); answer: the area of grassland is 112 square meters

The students of three classes in grade six go to plant trees. There are 80 trees in class one. The trees planted in class two are 7 / 8 of class one. The trees planted in class three are 5 more than 6 / 7 of class two. How many trees are planted in class three?

The number of trees planted in the second class is 80 × 7 / 8 = 70, and the number of trees planted in the third class is 70 × 6 / 7 + 5 = 65

Students plant trees. There are 560 trees planted in grade five and six. There are 80 more trees planted in grade six than in grade five. How many classes are there in each of the two grades?

If the fifth grade is x trees, the sixth grade is (x + 80 trees) x + X + 80 = 560, 2x = 480, x = 240, 240 + 80 = 320, the sixth grade is 320, the fifth grade is 240

There are 186 trees planted in grade 3 and grade 6. How many trees are planted in grade 3,

If x trees are planted in the third grade, 2x trees are planted in the sixth grade
According to the title: x + 2x = 186
3x=186
x=62
That is to say, 62 trees are planted in the third grade and 124 trees are planted in the sixth grade
A:,
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Hope to adopt

Students have to plant 120 trees. Two thirds of them were planted on the first day, of which two fifths were planted in the sixth grade. How many trees were planted in the sixth grade on the first day?

On the first day of planting, 120 times two-thirds = 80 (trees) on the sixth grade, "80 times two fifths = 32"

In order to beautify the environment and purify the air, a rectangular lawn with an area of 224 square meters is paved in Lvyuan community, which is 8 meters wide
Now, the width will be increased to 24 meters, and the length will not change. What is the expanded area

224÷8×24=672（m2）

It is planned to lay an isosceles triangle green space with a side length of 10 meters with 30 square meters of turf in a residential area. Please find out the length of the other two sides of this isosceles triangle green space

I can't see the number clearly. I took another shot

The perimeter of a rectangle is 48 cm, and the ratio of length to width is 5:3. How about the area of the rectangle?

The sum of length and width is 48 △ 2 = 24 cm
5+3=8
Length: 24 × 5 / 8 = 15 cm
Width: 24 × 3 / 8 = 9 cm
Area: 15 × 9 = 135 square centimeter

The length and width of a rectangle are prime numbers, and the perimeter is 56 cm. What is the maximum area of the rectangle? What is the minimum area?
solve

A:
The length and width of a rectangle are prime numbers a and B
So: 2 (a + b) = 56
So: a + B = 28
Because: A and B are prime numbers, then:
A = 2, B = 26 are not consistent
A = 3, B = 25, not in conformity
a=5,b=23
A = 7, B = 21, not in conformity
a=11,b=17
A = 13, B = 15
a=17,b=11
A = 19, B = 9 do not conform
a=23,b=5
So: the length and width in line with the meaning of the question are 5, 23 or 11, 17
Area s = AB = 115 or 187
So: the maximum area is 187, and the minimum area is 115