Forge a square steel piece with 4 decimeters of edge length into a cuboid with an area of 20 square meters. What is the height of the cuboid

Forge a square steel piece with 4 decimeters of edge length into a cuboid with an area of 20 square meters. What is the height of the cuboid

4x4x4 divided by 20

A square billet with an edge length of 4 decimeters is forged into a cuboid with an area of 20 square decimeters. The height of the cuboid is______ Decimeter

4 × 4 × 4 / 20 = 64 / 20 = 3.2 (decimeter). Answer: the height of this cuboid is 3.2 decimeter. So the answer is: 3.2

A square steel ring with 2 meters edge length is cast into a cuboid steel ring with an area of 200 square decimeters. The height of the cuboid steel ring is () meters

Cube volume: 2 × 2 × 2 = 8 cubic meters
So: the cuboid volume is 8 cubic meters
And cuboid volume = base area × height
The cuboid bottom area: S = 200 square decimeters = 2 square meters
So: cuboid height = cuboid volume ／ bottom area = 8 ／ 2 = 4m

As shown in the figure, a large rectangle is divided into four small rectangles. The areas of three small rectangles are 24 square centimeter, 30 square centimeter and 32 square centimeter respectively

Let the area of shadow part be x square centimeter, then: 32: x = 24:30, & nbsp; 24x = 32 × 30, & nbsp; & nbsp; X = 40; a: the area of shadow part is 40 square centimeter

The area unit of a rectangle is divided into four small rectangles. The areas of three small rectangles are 24, 30 and 32 respectively
Unit: square centimeter

If four small quadrangles are adjacent, the length and width are (4,6) (4,8) (5,6), and the shadow area is 8 * 5 = 40

The perimeter of the rectangle is 24 cm. What is the area of the largest semicircle in the rectangle?
The length of a rectangle is the diameter of the semicircle, and the width is the radius of the semicircle

1. The length and width of rectangle are respectively: [(24 △ 2) / (2 + 1)] × 2 = 8 (CM): [(24 △ 2) / (2 + 1)] × 1 = 4 (CM)
That is: the diameter of the circle is 8 cm, the radius is 4 cm
The area of the largest semicircle is: 1 / 2 × 3.14 × 4 & # 178; = 3.14 × 8 = 25.12 (square centimeter)

There is a circle with a circumference of 50.24. The area of the circle is equal to that of another rectangle. How long is the rectangle?
Please tell me the formula and why,
The circumference of the rectangle doesn't tell us, so it's unknown.

If the diameter of a circle is equal to the length of a rectangle, the height of the rectangle is equal to π
The length of rectangle = 50.24 △ 3.14 = 16 (CM)

The circumference of a rectangle is 30cm, in which the length is twice the width. What is the length and width of the rectangle?

Width: 30 △ 2 △ 3 = 5 (CM), length: 5 × 2 = 10 (CM), answer: the length of rectangle is 10 cm, width is 5 cm

The ratio of length to width of rectangle is 3:2, and the circumference of rectangle is 30cm

30 △ 2 = 15 (CM), 15 × 32 + 3 = 9 (CM), 15 × 22 + 3 = 6 (CM); a: its length is 9 cm and its width is 6 cm

The ratio of length to width of the two rectangles is 2:1. The width of the large rectangle is 3cm more than that of the small rectangle. The perimeter of the large rectangle is twice that of the small rectangle. Calculate the area of the two rectangles

Let the width of the small rectangle be xcm, then the length of the small rectangle be 2xcm, the width of the large rectangle be (x + 3) cm, and the length of the large rectangle be 2 (x + 3) cm. According to the meaning of the question, we can get 2 [x + 3 + 2 (x + 3)] = 2 × 2 (x + 2x), and the solution is: x = 3, then the area of the small rectangle is 2 × 3 × 3 = 18 (cm2); the area of the large square is 2 × (3 + 3) × (3 × 3) = 72 (cm2)