As shown in the figure, in △ ABC, ab = AC, D is a point on the edge of BC, with AB and BD as adjacent sides, make parallelogram ABDE and connect AD and EC

As shown in the figure, in △ ABC, ab = AC, D is a point on the edge of BC, with AB and BD as adjacent sides, make parallelogram ABDE and connect AD and EC


It is proved that: ∵ AB = AC, ∵ ABC = ACB, ∵ quadrilateral ABDE is parallelogram, ∵ ab ∥ De, ab = De, ∵ ABC = EDC, ∵ ACD = EDC, ∵ AB = AC, ab = De, ≌ AC = de. in △ ADC and △ ECD, AC = De, ACD = edccd = DC, ≌ ADC ≌ ECD (SAS)



In △ ABC, BD and CE are the midlines on the edges AC and ab. BD and CE intersect at point o. ① what is the relationship between the length of Bo and OD? Please prove. 2. Does the center line on the side of BC necessarily cross point o? Why?


① The reason is as follows: connecting de. ∵ BD and CE is the midline on the side AC and AB, ∵ de ∥ BC, de = 12bc. ∵ ode ≓ OBC, ∥ obod = BCDE, that is, Bo = 2od. ② the midline on the side BC must pass through point O. the reason is: making the midline AF on the side BC, intersecting BD to m, connecting DF, ∵ BD and AF are the midline on the side AC and BC, ∥ DF ∥ Ba, DF = 12ba. ∥ MDF ∥ MBA, ∥ dmbm = FMAM = dfab = 1 2, that is, BD = 3DM, ∵ Bo = 23bd, ∵ O and M coincide, that is, the middle line on the edge of BC must pass through point o



As shown in the figure, in the triangle ABC, BD and CE are the midlines on the sides AC and ab respectively. What is the relationship between the intersection of BD and CE and the length of Bo and OD?
(parallelogram rectangle diamond Square)





A trapezoidal decorative board, upper bottom 6 decimeters, lower bottom 10 decimeters, 1 meter high, both sides should be painted, painted area is () square decimeters


1 m = 10 decimeters;
Area of two sides
=2 × (upper bottom + lower bottom) × height △ 2
=(6+10)×10
=160 (square decimeter)



The shape of an iron plate is shown in the figure. Paint the two sides of the iron plate. What is the area of the paint? (unit: decimeter)


8 × 8 + (4 + 2 + 4 + 2) × (10-8) △ 2 = 64 + 12 × 2 △ 2 = 64 + 12 = 76 (square decimeter) 76 × 2 = 152 (square decimeter) a: the area of painting is 152 square decimeter



As shown in the picture, use a round iron plate with an area of 54 square meters to cut out 7 campus row iron plates of the same size, and the remaining iron plate surface
As shown in the figure, use a round iron plate with an area of 54 square meters to cut seven small round iron plates of the same size. What is the area of the remaining iron plate?


Direct use of 54 / 7 is about 7.714
Then 54-7 * 7 = 5 square meters



How much is the shadow area after cutting a circle on a square iron plate with a side length of 30 cm


Square area = 30 * 30 = 900 square centimeter
Circular area = 3.14 * 15 * 15 = 706.5 square centimeter
Shadow area = square area - circle area = 193.5 square centimeter



To cut a square iron plate with an area of 36m2, what is its side length


Because:
36=6*6
So the side length is 6 meters
Or:
Root 36 = 6M



On the circular iron plate with a radius of 20cm, if you want to cut a square iron plate with the largest area as a machine part, find the side length of the largest square(
Cut a square iron plate with the largest area from a circular iron plate with a radius of 20cm for machine parts, and calculate the side length of the largest square. (the error is not more than 0.1cm)


The diagonal of a square is equal to the diameter of a circle
Square area: 1 / 2 * 40 * 40 = 800
Square area = side length * side length = 800, side length = 28.3