Given that the circle O is the circumscribed circle of triangle ABC, and the side length is 6, the radius of circle O is calculated

Given that the circle O is the circumscribed circle of triangle ABC, and the side length is 6, the radius of circle O is calculated


If the side length is 6, then the height of an equilateral triangle is equal to 3 root sign 3. The intersection of the three midlines is the center of the circumscribed circle, and its distance from the vertex of each triangle is equal to two-thirds of the length of the midline
So, multiply 3 by 2 / 3 to get 2 root sign 3. So the radius of this circle is equal to 2 root sign 3



If the three sides of a triangle are 6 8 10, the radius of its circumcircle is


From 6 ^ 2 + 8 ^ 2 = 10 ^ 2, it can be determined that the triangle ABC is a right triangle
The diameter of the circle is the hypotenuse of the right triangle ABC, equal to 10
That is, the diameter of the circumcircle of the triangle is 10
The radius of circumcircle is 5



See who is smart: in the right triangle ABC, if the hypotenuse AB is 2 and the inscribed circle radius is r, then the maximum value of R is?


When the triangle is an equilateral triangle, the radius of the inscribed circle is r, which is the maximum. When the two radii of the circle are perpendicular to the two right angles, a square is formed, and half of the right angle is equal to R, so r = the root of 2