Why is displacement in VT image area

More precisely, the displacement is equal to the area, because s = vt
According to the area formula of the rectangle, the area of the image can be obtained by adding up the area of countless small rectangles, and the accumulated result is the displacement

In the V-T image, the displacement is the area of the trapezoid; in the x-t image, the displacement is the value on the Y axis corresponding to a certain time. Right?

It can be said that it is right
However, the first statement is not very reasonable
It should be said that: in V - t image, the displacement is equal to the area of trapezoid (sometimes it may be triangle, etc.)

Is v velocity or velocity in VT graph?

Speed

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