How many days does it take for a snail to climb a 7m bamboo pole, 4m in the daytime and 3M in the evening?

7-4=3
So when she got to 3 meters, she only had to climb 4 meters during the day
Rise 4-3 = 1m per day
3÷1=3
So it takes three days to reach three meters
3+1=4
A: it takes four days to climb

If a snail advances 4 meters every day, retreats 2 meters at night, and climbs up the shaft wall from the bottom of a 12 meter deep well, how many days can a snail climb to the wellhead?
(12-4) / (4-2) + 1 = 5 who knows where the plus one comes from?

On the last day, you don't have to climb out

A well is 5 meters high. The snail climbs 2 meters during the day and slides down 1 meter at night. How many days can it climb out of the well? The calculation formula is worked out
Set up the calculation formula of Xiangxi

5-2 + 1-2 + 1-2 + 1-2 = 0 (m)
5 △ 1-1 = 4 (days)

A snail climbs up from the bottom of a dry well. It climbs up 3 meters during the day and slides down 2 meters at night,
How many days does it take this snail to climb to the well head
process

15 days
Climbing 3 meters in the daytime and falling 2 meters in the evening, that is to say, climbing 3-2 = 1 meter in one day, climbing 13 meters in 13 days, climbing 3 meters 13 + 3 = 16 in the daytime in the 14th day, falling 2 meters in the evening is 14 meters, and climbing 14 + 3 = 17 in the 15th day is just out of the wellhead

Xiaoli's room is 4m long, 3M wide and 2.8m high
Xiao Li's room is 4m in length, 3m in width and 2.8m in height. She needs to paint the walls and roof with pink paint (excluding 4.5 square meters of doors and windows). On average, she uses 0.3 kg of paint per square meter. How many kg of paint do she need?

Painting area = 4 × 3 + 4 × 2.8 × 2 + 3 × 2.8 × 2-4.5 = 51.2-4.5 = 46.7 square meters need paint = 46.7 × 0.3 = 14.01 kg ~ I wish you learning progress ~ ~ ~ hope you can timely "choose as a satisfactory answer", your adoption is my driving force forward~~~

There is a rectangular platform, 6m in length and 3M in width, with a carpet twice the area of the platform. When it is laid on the platform, the length of each side is the same, so it is necessary to calculate the height of the carpet
What's the width and width

Let X be the vertical length
6*3*2=(6+x)*(3+x)
36=18+9x+x^2
x^2+9x-18=0
(x+9/2)^2=18+81/4
According to the meaning of the title, x = [(root 153) - 9] / 2 = [12.4-9] / 2 = 1.7
Therefore, the carpet is 6 + 1.7 = 7.7m in length and 3 + 1.7 = 4.7m in width

As shown in the picture, lace of the same width is inlaid around a rectangular carpet. As shown in the picture, the rectangular pattern in the center of the carpet is 8 meters long and 6 meters wide, covering the entire surface of the carpet

You are short of conditions for this problem. Take a good look at the problem and the picture

A rectangular room with a carpet of 4 meters long and 3 meters wide in the middle and a floor of 1 meter wide around. How many square meters is the area of this room?

The area of this room is 4 * 3 + (4 + 3) * 1 * 2 + 1 * 1 * 4 = 12 + 14 + 4 = 30 square meters

As shown in the figure, the length of a carpet is 8m and the width is 5m. If the area of the rectangular pattern in the center of the carpet is 18m2, the width of the lace can be calculated

Let the width of lace be XM. According to the meaning of the question, we can get: (8-2x) (5-2x) = 18. The solution is X1 = 1, X2 = 112. After the test, X2 = 112 is not suitable for the meaning of the question. A: the width of lace is 1m

Lace of the same width is inlaid around a rectangular carpet. The rectangular pattern in the center of the carpet is 8 meters long and 6 meters wide. The area of the whole carpet is 80 square minutes
Solve quadratic equation of one variable

（8+2X）*（6+2X）＝80

How many days does it take for a snail to climb a 7m bamboo pole, 4m in the daytime and 3M in the evening?