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Given that the acute angle A. B satisfies Tan (a + b) = 2tana, the maximum value of Tana is?
tanA=tan[(B+A)-B]
=[tan(B+A)-tanB]/[1+tan2BtanB]
=tanB/[1+2(tanB)^2]
=1/[1/tanB+2tanB]
≤1/(2√2)
=√2/4
Given that the acute angle α satisfies Tan (α + 20 °) = 1, then the degree of the acute angle α is
Given that the acute angle α satisfies Tan (α + 20 °) = 1, the degree of the acute angle α is "25 °"
It is known that a is an acute angle and Tan (a) = 1 / 2
Find (sin2a × cosa Sina) / (sin2a × cos2a)
SIN2A=2SINACOSA
COS2A=(COSA)^2-(SINA)^2
Then the numerator and denominator are divided by cosa Sina
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