Given that the three sides of triangle ABC are m, N, √ m ^ 2 + Mn + n ^ 2, find the maximum angle of triangle ABC

Given that the three sides of triangle ABC are m, N, √ m ^ 2 + Mn + n ^ 2, find the maximum angle of triangle ABC

Let the angle opposite the edge of length √ m ^ 2 + Mn + n ^ 2 be angle 1
Then cos angle 1 = [M ^ 2 + n ^ 2 - (√ m ^ 2 + Mn + n ^ 2) ^ 2] / 2Mn = - 1 / 2
So the maximum angle of triangle ABC = angle 1 = 120 degrees

1: In the triangle ABC, ab = n ^ 2 + 1, BC = n ^ 2-1, AC = 2n, then angle a + angle B=_____ . and explain the reasons

Because the square of AB is equal to the square of BC plus the square of AC, the triangle ABC is a right triangle, and the angle ACB is a right angle, so the answer is 90 degrees

1) There are three relations R, s and t as follows: R (AB M1 N2) s (BC 13 35) t (ABC M13) is calculated by the relations R and s
If the relation T. is obtained, the operation used is
1) There are three relations R, s and t as follows: R (ABC A12 B21 C31) s (AD C4) t (ABCD c314) the relation t is obtained from the relation R and s by operation

Natural connection

In RT △ ABC, C = 90 ° AC = 12, Tana = 1 / 2, find BC and ab

tanA=1/2=AC/BC.
Because AC = 12
So BC = 6
Because right triangles
Pythagorean theorem
AB=6√5

In RT △ ABC, ∠ C = 90 ° if Tana = 2 / 3, BC = 10, find the length of AC and ab

Because Tana = 2 / 3, BC / AC = 2 / 3 (∠ C = 90 °) so AC = 15
According to Pythagorean theorem, ab = root sign (10 square + 15 square) = 5 root sign 13

In RT △ ABC, ∩ C = 90 °, Tana = 3 / 4, AC = 120, find the values of BC and ab

In RT △ ABC, ∠ C = 90 °, Tana = BC / AC = BC / 120 = 3 / 4
So, BC = 90
From Pythagorean theorem, it is easy to get AB = 150
Does "C = 90" mean "C = 90"

In RT △ ABC, ∠ C = 90 °, CPSA = 2 / 3, AC = 12, then ab=___ ,BC=___ ,tanA=___ .

AB = 18, BC = 6, root 5, Tana = 2 / 2 root 5

In RT △ ABC, ∠ C = 90 °, Tana = 23, AC = 4, then BC = 0___ ．

In RT △ ABC, ∠ C = 90 °, ∵ AB is hypotenuse, ∵ BC = AC · Tana = 4 × 23 = 83

In RT △ ABC, C = 90 degrees, Tana = 3 / 2, then SINB=____ ,tanB=___

Tana = BC / AC = 3 / 2, let BC = 3, AC = 2, then AB = √ 13
So SINB = AC / AB = 2 √ 13 / 13
tanB=AC/BC=2/3

In RT △ ABC, ∠ C = 90 ° and ∠ a = 45 °, then what is Tana + SINB

∵∠C=90°,∠A=45°
∴∠B＝180-∠A-∠C＝180-45-90＝45
∴tanA＝tan45＝1
sinB＝sin45＝√2/2
∴tanA+ sinB＝1+√2/2
∵∠C=90°,∠A=45°,∠A=45°
The ABC isosceles right triangle
About axisymmetry