Is one third x a monomial?

Is one third x a monomial?


It's a binomial, because a binomial, as long as its denominator is not 0 or a letter, can. This binomial can be written as one third of X, so it's a binomial, and it's also an integral



Table 2 and table 3 are selected from table 1 to find the value of a + B
Table 1 Table 2 Table 3
0 1 2 3.11 11 13
1 3 5 7.14 17 b
2 5 8 11.a
3 7 11 15.
.


a=17 b=20
From the vertical column, the next number in the first column minus the previous number will get 1, the second column will get 2, the third column will get 3, (Table 2 obviously belongs to the third column, according to the latter number minus the previous number to get 3, a is 17), the fourth column will get 4, and so on, the former column is smaller than the latter column by one, so Table 3 is 17-11 = 6, then the latter item should be b-13 = 7, so B is 20
It's wrong to be careless just now,



Observe Table 1 and find the rule. Table 2 and table 3 are part of Table 1 respectively, then the value of a + B is____ .
Table 1
0 1 2 3 …
1 5 5 7 …
2 5 8 11 …
5 7 11 15 …
… … … … …
Table 2: 11
fourteen
a
Table 3: 11 13
17 b
None of the three tables is wrong


Fill in some more and you'll see Table 1: 0 123 45 6.13 57 9 11 13 2 5 8 11 14 17 20.3 7 11 15 19 23 27.4 9 14 19 24 29 32… … … … … 11 17 23 29 35 41. Table 2: 1114a Table 3: 11 1317 B obviously: A is 17, B is 20, a + B = 37



Table 2, table 3 and table 4 are part of Table 1, in which the values of a, B and C are the same
Table 1: 1, 2, 3, 4
2、4、6、8、.
3、6、9、12、.
4、8、12、16、.
Table 2: 12
fifteen
a
Table 3: 20, 24
25、b、
Table 4: 18
c
thirty-two


Total arithmetic of any row and column
a-15=15-12
a=18
b=30
c=24



Table 2, table 3 and table 4 are part of Table 1, in which the values of a, B and C are the same
Table 1: 1, 2, 3, 4
2、4、6、8、.
3、6、9、12、.
4、8、12、16、.
Table 2: 12
fifteen
a
Table 3: 20, 24
25、b、
Table 4: 18
c
thirty-two
The process of getting C
I want the process


a=18,b=29,c=25(18+7=25.,25+7=32)



Observe Table 1 to find the rule. Table 2, table 3 and table 4 are part of Table 1. The values of a, B and C are ()
A. 20,29,30B. 18,30,26C. 18,20,26D. 18,30,28


Table 2 intercepts one of the columns: the difference between the upper and lower numbers is equal, so a = 15 + 3 = 18. Table 3 intercepts four adjacent numbers of two rows and two columns: the difference of the right column should be 1 larger than that of the left column, so B = 24 + 25-20 + 1 = 30. Table 4 intercepts six numbers of two rows and three columns: 18 is 6 times of 3, then C should be 7 times of 4, that is 28



Observe Table 1 to find out the rules. Table 2, table 3 and table 4 are the parts intercepted from table 1, in which the values of a, B and C are____ .
A.20,29,30
B.18,30,26
C.18,20,26
D.18,30,28
Table 1
1 2 3 4…
2 4 6 8…
3 6 9 12…
4 8 12 16…
… … … … …
Table 2
twelve
fifteen
a
Table 3
20 24
25 b
Table 4
eighteen
c
thirty-two


Answer: B
Analysis: in Table 1, the difference between horizontal and vertical adjacent numbers is the same, and the difference number of each column increases by 1 according to the row



Observe Table 1 to find the rule. Table 2 is a part of Table 1, where the values of a, B and C are(
Observe Table 1 to find the rule. Table 2 is a part of Table 1, where the values of a, B and C are(
Table 1 Table 2
1 2 3 4 … 16 a
2 4 6 8 … 20 b
3 6 9 12 … c 30
4 8 12 16 …
… … … …
A.20,25,24
B.25,20,24
C.18,25,24
D.20,30,25


Option a
In line 4, 4,8,12,16, the difference is 4, so: a = 20
In the fourth column, the difference between 4, 8, 12, 16 and 20 is 4,
So: C = 24
In line 5, the difference between 5, 10, 15 and 20 is 5, so B = 25
So: A, B and C are 20, 25 and 24 respectively



-1+3-5+7-9+11-...-393+395-397+399
It's better for the teacher to understand


Two solutions: a total of 200 numbers. Method 1: one negative one positive for a group, (- 1 + 3) + (- 5 + 7) + +(-397+399)=2+2+2+… +2 = 2 * 100 = 200 method 2: all positive numbers into a group, all negative numbers into a group: use the arithmetic sequence summation formula s positive = Na1 + n (n-1) d / 2 = 3 * 100 + 100 * (100-1) * 4 / 2 s negative = -



The value of 1 + 3 + 5 + 7 + 9 +. + 399 is 40000. How can we get it?


Arithmetic sequence (1 + 399) X200 △ 2 = 40000 (first term + last term) × number of terms △ 2