How to solve (3x + 18) - 101 = x + 101,

How to solve (3x + 18) - 101 = x + 101,

3x+18-101=x+101
2x=202-18
x=101-9=92

3x-60 = x + 60 to solve the equation

Transference
3X-X=60+60
2X=120
X=120÷2
X=60

60% X-10 = 1 / 3x to solve the equation

60％x－10＝1/3x
3/5x－1/3x＝10
9/15x－5/15x＝10
4/15x＝10
x＝10÷4/15
x＝37.5
Don't understand can ask!

The absolute value a is equal to 1. Find the value of the square + (a + 5) x + 2 = 0 of the quadratic equation (A-1) x with respect to X

|a|=1
A = 1 or a = - 1
If the equation is a quadratic equation of one variable, then the coefficient of quadratic term is not equal to 0
a-1≠0
a≠1
So a = - 1
The original equation is changed into:
-2x²+4x+2=0
x²-2x-1=0
Discriminant △ = 4 + 4 = 8
x=(2±2√2)/2=1±√2

The function f (x) is defined on (0, + ∞), and the x power of F (E) = the x power of X + E

Let e ^ x = t
f(t)=lnt+t f(x)=lnx+x
Let g (x) = f (x) - 2x + 1 = lnx-x + 1
g'(x)=1/x-1
When 0

Given the function f (x) = 2x power of a, x power of 3A + 2 (a > 0), find the minimum value of F (x)

F (x) = 2x power of a - x power of 3A + 2 = (a ^ x-3 / 2) ^ 2 + 2-9 / 4 = (a ^ x-3 / 2) ^ 2-1 / 4
So the minimum value of F (x) is - 1 / 4

Function f (x) = (a2x power - 1) / (2x power + 1). Find the range of the function
The function f (x) = (a2x power - 1) / (2x power + 1) is an odd function defined on R. Find the range of the function

F (x) = (a2x power - 1) / (a2x power + 1) = 1-2 / (a2x power + 1)
Let a2x power + 1 = T. then t is greater than 1
Y = 1-2 / T.T ∈ (1, positive infinity)
So the range is (- 1,1)

Cross multiplication of quadratic equation of one variable detailed solution ～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～～
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Did you learn cross multiplication when factoring?
If you can't do this, you'd better go to the teacher It's difficult to say
If you will:
The algebraic formula is as follows: x ^ 2-x-6 = (x-3) (x + 2), right?
Then the equation x ^ 2-x-6 = 0 becomes
(x-3)(x+2)=0
So (x-3) = 0 or (x + 2) = 0
So x = 3 or x = - 2

What is cross multiplication of quadratic equation with one variable?

The so-called cross phase multiplication is to use the inverse operation of the multiplication formula (x + a) (x + b) = x ^ 2 + (a + b) x + AB to factorize. For example, factorize x ^ 2 + 7x + 12. 12 can be decomposed into 3 × 4, and 3 + 4 is exactly equal to the coefficient 7 of the primary term. Therefore, the above formula can be decomposed into: x ^ 2 + 7x + 12 = (x + 3) (x + 4)

Factoring factor 2x ^ 2-x-3 by cross phase multiplication

1 1
×
2 -3
The coefficient of X is 1 * (- 3) + 2 * 1 = - 1
So the original formula = (x + 1) (2x-3)