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In the proportion of 4:12 = 8:24, if the latter term of the first ratio is increased by 6, how can the former term of the second ratio be changed to make the equation hold
4: 12 = N4: N12, so the ratio of n to n is constant
4：12+6=4：18=n4:n18=8：36
If you want to keep 24 constant, multiply 8:36, numerator and denominator by 4 / 6 at the same time, and the numerator will come out
I haven't thought about the rules, but it's not difficult to be considered necessary. Of course, when it comes to the inquiry questions, I don't know if there are rules
8. The equation of 10,12,8 = 24
Use addition, subtraction, multiplication and division instead of repeating numbers
(12-10)x8+8=24
(1) (2) the ratio of 4:8 and 12:24 is () of,
(1) there are countless ratios equal to the ratio of 0.6:0.2
(1) Write out two ratios that are one fifth of the ratio: (1:5) and (3:15), and the ratio of composition is (1:5 = 3:15). (2) the ratio of 4:8 and 12:24 is (equal), both are (1,2), so the ratio they can make up is (4:8 = 12:24). Judgment: (1) there are countless ratios equal to the ratio of 0.6:0.2. (correct)
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