The slope of the tangent of the curve y = x & # 179; - 2x + 4 at (1,3) is Urgent need

The slope of the tangent of the curve y = x & # 179; - 2x + 4 at (1,3) is Urgent need

Derivation y '= 3x & # 178; - 2
When x = 1, y ′ = 1
The slope k = 1

How to calculate the slope of origin
I saw an answer that was analysis fitting fit linear open dialog, but I didn't see open dialog after I ordered fit linear

8.0

How to calculate slope with least square method on origin

I hope it can help the owner. After all, other functions will be used in the future. It's better to see the function introduction

78×56＋27×78＋13×83＋83×9

78×56＋27×78＋13×83＋83×9
= 78×（56+27）+83×（13+9）
= 78×83+83×22
= 83×（78+22）
= 83×100
= 8300

Simple algorithm of 0.8 * 0.25 * 0.4 * 12.5

0.8×0.25×0.4×12.5=0.25×0.4×0.8×12.5=0.1×10=1

12.5 * 0.25 * 3.2 what is the simple algorithm

3.2 can be divided into 0.8 times 4, 12.5 times 0.8 and 0.25 times 4

Simple algorithm of 12.5-3.25 * 1.8

12.5-3.25*1.8
=12.5-12.5*0.26*1.8
=12.5(1-0.468)
=12.5*0.532
=12.5*8*0.0665
=100*0.0665
=6.65

A simple algorithm of (2.8 * 25 + 12) / (28 * 2.5)
Simple algorithm!
Simple algorithm!

(2.8*25+12)/(28*2.5)
=(2.8*25/(28*2.5)+12/(28*2.5)
=1+6/35
=1 and 6 / 35

The detailed solution of 1-8x + 16x ^ 2 = 2-8x

1-8x+16x^2=2-8x
16x^2-1=0
(4x+1)(4x-1)=0
16(x+1/4)(x-1/4)=0
x=-1/4,x=1/4

Solving 16x & # 178; + 8x + 1 by factor method
Let's divide x (16x + 8) + 1 = 0 so that there are two factors on the left, and X (16x + 8) = - 1. But this does not conform to the general form a · B = 0. How can we calculate it
Or, how to find the factorial solution of the formula ax & # 178; · BX + C (C is an arbitrary number with no regularity)

Perfect square
The original formula = (4x + 1) &# 178;