If - 2 < x < 3, simplify x + 2 + x-4

If - 2 < x < 3, simplify x + 2 + x-4

|x+2|+|x-4|=x+2-(x-4)=6
The process of removing the absolute value sign is to judge whether the result in the absolute value sign is positive or negative. If it is positive, remove the absolute value directly, and if it is negative, remove the absolute value and add a negative sign

If - 2 ≤ x ＜ 4, simplify x + 2 - 3 x - 4

∵ - 2 ≤ x < 4 ∵ - 2 + 2 ≤ x + 2 < 4 + 2, that is, 0 ≤ x + 2 < 6 ∵ x + 2 ∵ - 2 ≤ x < 4 - 2-4 ≤ x-4 < 4-4, that is, 6 ≤ x-4 < 0 ∵ x-4 = - (x-4) = 4-x ∵ 3 ∵ x-4 ∵ 3x (4-x) = 12-3x, the original formula = x + 2 - (12-3x) = x + 2-12 + 3x = 4x-10

Simplify x-3-4-x, where x is less than 3
When x = 1, the value of the algebraic formula ax & # 179; + BX-1 is 5. When x = - 1, find the value of the algebraic formula ax & # 179; + BX-1

Because | x-3 | - | 4-x |, where x < 3
So | x-3 | - | 4-x | = - (x-3) - (4-x) = 3-x-4 + x = - 1
x=1,ax^3+bx=5+1=6
x=-1,
ax^3+bx-1
=a(-x)^3-bx-1
=-(ax^3+bx)-1
=-6-1
=-7