Inequalities with absolute values 1.|x^2-1|
1.∵|x^2-1|
RELATED INFORMATIONS
- 1. On the linear inequality of one variable with absolute value~ Given that the solution set of inequality | a-2x | B (b > 0) is {x | x > 4 or X < - 5}, find a-b The finer the better Good answer I will add more points
- 2. 3(x+8)-5=-4(2x-7) This is the equation
- 3. When - 1 < x < 2, simplify X-2 - x + 1
- 4. It is known that x is a rational number greater than - 2 and less than 3, and the reduction of x = 2 - X - 3
- 5. If x > 4 is known, simplify x-3 + 4-x
- 6. If a is known to be greater than 1, simplify A-1 + A + 2 Then summarize the solution skills (inequality, which I don't quite understand)
- 7. If - 2 < x < 3, simplify x + 2 + x-4
- 8. [urgent] simplify x-3-4-x, where x is less than 3
- 9. If - 3
- 10. a. B is opposite to each other, C and D are reciprocal to each other, M = 4, find the value of 2A - (CD) 178; 186; 186; 185; + 2b-3m
- 11. Given that the slope of a tangent line of the curve y = x2-3lnx is 5, the abscissa of the tangent point is 0
- 12. How to calculate tangent slope of curve at a certain point in Excel
- 13. The slope of the tangent of the curve y = x & # 179; - 2x + 4 at (1,3) is Urgent need
- 14. Let the tangent slope of point m on the curve y = x ^ 2 + X + 2 be - 3, and the coordinates of point m are () a: (- 1,2) B: (1,4) C: (- 2,4) d: (0,2)
- 15. It is known that there is a point a (2,0) B (1,1) on the square of the curve y = 2x-x, and the slope of the tangent passing through point a
- 16. Find the tangent slope of the curve y = 3x ^ 2-1 at x = 1?
- 17. Slope and derivative Given the curve y = f (x), and the point m (x, y) on the curve, is the derivative of X into y the tangent slope at M? How can I find the tangent of m if M (x, y) is not on the area line?
- 18. After deriving a curve, is the slope of the tangent passing through a certain point equal to the derivative?
- 19. Given that l is the tangent at any point on the image of the function f (x) = 4x / (x ^ 2 + 1), the range of tangent slope is calculated
- 20. The position relationship between the tangent with the smallest slope on the curve C: y = (x ^ 2 + 1) / 2 + ln X and the circle x ^ 2 + y ^ 2 = 1