In a glass bottle, the original salt is 1 / 11 of the water. After adding 15 grams of salt, the salt accounts for 1 / 9 of the brine. How many grams of the original brine are in the bottle?

In a glass bottle, the original salt is 1 / 11 of the water. After adding 15 grams of salt, the salt accounts for 1 / 9 of the brine. How many grams of the original brine are in the bottle?

According to the title, if x grams of salt are in the bottle, then the water is 11x
After adding 15 grams of salt, (15 + x) / (11x + X + 15) = 1 / 9, x = 40
So the original salt water in the bottle is 12x = 480g
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A cup of salt water, salt accounts for 1 / 5 of the salt water, now the cup of salt water evaporation, evaporation of 20 grams of water, salt accounts for 1 / 4 of the salt water, the original salt and water each more
Shaoke

Suppose the composition of salt is x, then because "a cup of salt water, salt accounts for one fifth of salt water", the original composition of water is 5x;
Let the weight of brine be y
5x=y
y-20=4x
The solution is x = 20; y = 100
The original salt was 20 grams
Original water: 100-20 = 80g
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In 450 grams of 20% salt water, after adding 50 grams of salt, what is the salt content of salt water at this time?

In 450 grams of 20% salt water, after adding 50 grams of salt, the salt content of salt water is 28%
(450×20%+50)÷(450+50)=28%

2 / 5-x = 1 / 7 solution equation 7 / 9 + x = 11 / 12 solution equation x + (4 / 5-1 / 4) = 4 / 3 solution equation
5x + 5 / 9 = 5 / 9 to solve the equation
3 / 8-1 / 4 + x = 7 / 15

1.2/5-x=1/7 x=2/5-1/7 x=9/352.7/9+x=11/12 x=11/12-7/9 x=5/363.x+(4/5-1/4)=4/3 x=4/3-11/20 x=47/804.5x+5/9=5/9 5x=0 x=05.3/8-1/4+x=7/15 1/8+x=7/15 x=7/15-1/8 x=41/120

How to solve the equation x + 4 / 9 = 7 / 12

4 / (x + 9) = 7 / 12, cross multiply, 4x12 = 7 (x + 9). X = - 15 / 7

Solving equation 12 and 1 / 4-x = 7 and 5 / 6
(1 + 2 / 7) x = 72

① Original deformation:
49/4-x=47/6
49×3-12x=47×2
12x=94-147
x=-53/12
②（1+2/7）x=72
9x/7=72
9x=72×7
x=56

Solving equation x ratio (x-3) = 7:5 ratio and proportion

X ratio (x-3) = 7 to 5
5x=7(x-3)
5x=7x-21
2x=21
x=10.5

On the solution of percentage equation x + 13% - 28% = 3.4

X+13%-28%=3.4
（X+13%-28%）*100=3.4*100
100X+13-28=340
100X=355
X=3.55

Percentage solution equation X-15% x = 37.4 three quarters x-25% x = 12

x-15%x=37.4
85% x = 37.4 (take x as "1", then 1-15% = 85%)
X = 44 (divide 37.4 by 85%, that is, divide 37.4 by 17 / 20 to get 44)
3/4x-25%x=12
　　　　 1/2x＝12
　　　　　　x＝12÷1/2
　　　　　　x＝24

1.3（x＋2）＝4（x＋1) 2.（x—12)×8÷2＋23＝35
4.3 (x + 2) = 4 (x + 1)
11 - (three and two thirds - x) = 8

The solution 1.3 (x + 2) = 4 (x + 1) 2. (x - 12) × 8 △ 2 + 23 = 353x + 6 = 4x + 4 (x - 12) × 4 = 35 - 236 - 4 = 4x - 3x 4x - 48 = 12  x = 24x = 60  x = 153