In the triangle ABC, angle a is greater than or equal to angle B is greater than or equal to angle c, and angle a is greater than or equal to angle c by 51 degrees. Find the maximum value of angle B

In the triangle ABC, angle a is greater than or equal to angle B is greater than or equal to angle c, and angle a is greater than or equal to angle c by 51 degrees. Find the maximum value of angle B

A>=B>=C
A-C=51°,C=A-51°
And because: a + B + C = 180 degree
So: 180 ° = a + B + C
=A+B+A-51°
=2A+B-51°>=2B+B-51°=3B-51°
So: 3B

What is 52 + 69 + 47 + 51 * 8 + 29 + 42 * 76-53?

3744

Given a + B + C = 2, find the maximum value of ABC
The first problem is to find the angle a is equal to 60 degrees, and the triangle ABC is inside

A = 2 - (B + C), the maximum value of ABC is the maximum value of BC [2 - (B + C)],
Then, cosa = B & # 178; + C & # 178; - A & # 178; / 2BC = 1 / 2 is simplified,
After my simplification, it can be reduced to B + C = 1 + 3bC / 4,
The results show that ABC = (1-3bc / 4) BC = [(4 / 3-bc) BC] / (4 / 3),
According to the basic inequality XY

5(X-7)=26.5 4（X+8.2）=40.8 （X-0.52）÷4=1.12 1.5×(X-8)=60
Find the solution of the equation

5(X-7)=26.5
x-7=5.3
x=12.3
4（X+8.2）=40.8
x+8.2=10.2
x=2
（X-0.52）÷4=1.12
x-0.52=4.48
x=5
1.5×(X-8)=60
x-8=40
x=48

Solution equation: X * 2.52% * 1 * (1-5%) = 20478.8
Grandfather Li deposited a sum of money in the bank last year, with a fixed term of one year and an annual interest rate of 2.52%. After maturity, grandfather Li got 20478.8 yuan with interest and principal. What is the principal of grandfather Li deposited in the bank (the interest rate is 5%)?

Suppose: the principal is x yuan. X + X * 2.5% * (1-5%) = 20478.8 x = 2000

S = one in fifty is known One in sixty, so what's the integer part of S

1/51+1/52+1/53+.+1/59+1/60
＜1/50+1/50+1/50+1/50+1/50+1/50+1/50+1/50+1/50+1/50
=1/50×10
=1/5
=0.2
∴0＜1/51+1/52+1/53+.+1/59+1/60＜0.2
The integer part is 0

From the number - 52, add 1 step by step to get a column of integers: - 51, - 50, - 49
Q:
(1) What is the 100th number? (2) find the sum of these 100 numbers

(1) The hundredth number is: - 52 + 100 = 48
(2) Sum = - 52-51-50-49 - (48-47 -... - 2-1-0 + 1 + 2 +... + 47 + 48)
=-52-51-50-49
=-202

2 ×[-（ 3/2）]×（4/3）×[-（5/4）]…… ×[-（51/50）]
2 ×[-（ 3/2）]×（4/3）×[-（5/4）]…… ×[-（51/50）]=?

-27, right
I use VB6
Private Sub Command1_ Click()
Dim ans As Integer
For i = 2 To 50 Step 2
ans = ans + (-(i + 1) / i) * ((i + 2) / (i + 1))
Next i
MsgBox ans
End Sub

6.73-4.51 + 1.73 = [] with simple calculation

4

Simple calculation; (38 × 1 / 5 + 17 × 1 / 5) × 33 / 7

(38 × 1 / 5 + 17 × 1 / 5) × 33 / 7
=(38 + 17) × 1 / 5 × 7 / 33
=55 × 5 / 1 × 33 / 7
=11 × 7 / 33
=Two and one-third