In the salt rate of 10% of 450 grams of salt water, add 50 grams of salt, then the salt rate of salt water is half a few

In the salt rate of 10% of 450 grams of salt water, add 50 grams of salt, then the salt rate of salt water is half a few


(450×10%+50)÷(450+50)=19%
At this time, the salt content of brine is 19%



The salt content of new brine is ()
A. 9%B. 10%C. 15%D. 19%


450 × 10% ~ (450 + 50) × 100% = 45 / 500 × 100% = 9%. A: the salt content of fresh brine is 9%



Add 50 grams of salt to 450 grams of 10% salt water, and the salt content is ()%


Salt content = (450 × 10% + 50) / (450 + 50%) = 19%



Solving equation (2x -- 1 / 0.5 = x + 1 / 0.3)
2x--1/0.5=x+1/0.3
What's 5 / 8: x = 1 and 1 / 2: (5 -- 2 and 3 / 5) (⊙ o ⊙)?


2x--1/0.5=x+1/0.3
150(2x--1/0.5)=150(x+1/0.3)
300x-3=150x+5
150x=8
x=4/75
That's it. ^ 8^



Solution equation: (1 / 12-1 / x) * 5 + 1 / X * 3 = 7 / 20
"*" is a multiplication sign, 1 / 12 = one twelfth, and so on,


(1/12-1/x)*5+1/x*3=7/20
5/12-5/x+3/x=7/20
2/x=5/12-7/20
x=30



Solution equation: X * 50 / 7 * (3 / 4 * 5 / 9 * 5 / 12) = 7 / 20


Solution equation: X * 50 / 7 * (3 / 4 * 5 / 9 * 5 / 12) = 7 / 20
(50*3*5*5)x/(7*4*9*12)=7/20
x=(7*7*4*9*12)/(20*50*3*5*5)
=49*3*6/(5*25*5*5)
=882/3125



3 / 8x-37.5% x = 1 / 8.20% x + 1.2 = 4.75% - 1 / 4x = 12.5


3/8X﹣3/8X=1/8
(no solution) 37.5% = 0.375 = 3 / 8
20%X+1.2=4
0.2x+1.2=4
0.2x=2.8
x=14
75%﹣1/4X=12.5
0.75﹣1/4X=12.5
﹣1/4X=12.5- 0.75
﹣1/4X=11.75
X=-47



35-2.5x = 5 6 * 2.5 + 8x = 23 (2.5 + x) * 14 = 11.9 above is the solution of the equation! Be clear!
49.2-0.5*0.5-8.75
It's a trailer


35-2.5X=5
2.5x=30
x=12
When x = 12, 35-2.5x = 35-30 = 5
6*2.5+8X=23
15+8x=23
8x=8
x=1
When x = 1, 6 * 2.5 + 8x = 15 + 8 = 23
(2.5+X)*14=11.9
2.5+x=0.85
x=-1.65
Checking calculation: x = - 1.65 (2.5 + x) * 14 = 0.85 * 14 = 11.9



Equation checking: 8x-5x = 27
complete


8x-5X=27
3x=27
x=27÷3
x=9
Take x = 9 into the equation
8×9-5×9
=72-45
=27 = right
establish



2 / 3 + 20% x = 1 to solve the equation


0.2x=1/3
x=5/3