If the line y = 2x-6 moves 3 units to the left along the x-axis, and then 2 units to the up along the y-axis, the analytical expression of the line is

If the line y = 2x-6 moves 3 units to the left along the x-axis, and then 2 units to the up along the y-axis, the analytical expression of the line is


Y = 2x-6 (3 units left) → y = 2 (x + 3) - 6 = 2x, 2 units up → y = 2x + 2



If the lines L1 and L2 are symmetric about the X axis and the line L1: y = 2x + 1 is known, the equation of the line L2 is obtained


This is very simple. Take the points (0,1) (1,3) on the line L1. Their points about the x-axis symmetry are (0, - 1) (1, - 3) respectively. Then L2 is the line passing (0, - 1) (1, - 3). I believe you can finish it by yourself next!



Given that the line L1: y = 2x + 3, L1, L2 is symmetric about the y = x axis, please use some skillful methods to solve the linear equation of L2,


The simplest way: transfer in
Take point (x, y) on L2
Then the point (y, x) with respect to y = x is on L1
x=2y+3
Just sort it out