The monotone increasing interval of function y = Log1 / 3 (x ^ 2-6x + 5) is Why not (1,3)

This is a composite function
Domain of definition
x²-6x+5＞0
So (x-1) (X-5) > 0
So x ＜ 1 or X ＞ 5
Because y = Log1 / 3 (x) is a decreasing function
Then finding the monotone increasing interval of y = Log1 / 3 (X & # 178; - 6x + 5) is to find the monotone decreasing interval of y = x & # 178; - 6x + 5
And y = x & # 178; - 6x + 5 opening upward
So the monotone decreasing interval is (- ∞, 1)
That is, the monotone increasing interval of y = Log1 / 3 (X & # 178; - 6x + 5) is (- ∞, 1)
If you don't understand, I wish you a happy study!

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