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As shown in the figure, the image of the linear function y = KX + B passes through two points B and C, and the line am is perpendicular to X (1) Finding the analytic expression of the first order function (2) Finding the area of trapezoidal ABOM chart
The graph of a function passes through points c (- 3,0) and B (0,2)
be
b=2
-3k+b=0
k=2/3
So the analytic expression of a function is y = 2 / 3x + 2
(2)x=4,y=14/3
So the coordinates of point B are (4,14 / 3)
So the area of trapezoidal ABOM is 1 / 2 (2 + 14 / 3) * 4 = 40 / 3
The image of the first-order function passes through the point (- 2, - 5) and forms an isosceles triangle with the coordinate axis
Let y = KX + B, pass through (x, 0), (0, x) points, that is, KX + B = 0, B = x, BK + B = 0, B = 0 (rounding off), k = - 1, that is, the straight line becomes y = - x + B, substituting (- 2, - 5), then, - 5 = 2 + B, B = - 7,
The analytic expression of the function is y = - X-7
If △ ABC is an isosceles triangle, how many points c can satisfy the condition?
There are five of them and seven of them,
How many?
Write the reason!
5
Intersection of linear function and coordinate axis and (1,0), (0, - 1)
When AB is waist
There is a point (0,1) on the y-axis,
(0, - 1-change 2)
On the x-axis
(-1,0),(1+√2,0),
Finally, don't forget the origin
RELATED INFORMATIONS
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