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If the image of a linear function passes through point a (- 2, - 1) and is parallel to the line y = 2x-3, the analytic expression of the function is () A.y=x+1 B.y=-3x-1 C.y=3x+1 D.y=3x-1
Option a
If the image of a function of degree is parallel to the line y = - x + 5 and passes through the point (8,2), then the analytic expression of the function of degree is
If the graph of a linear function is parallel to the line y = - x + 5, then its slope is the same as that of the line y = - x + 5, that is, k = - 1
Let the linear function be y = - x + B
Because it passes through point (8,2), we substitute it into the equation
2=-8+b
b=10
So the linear function is y = - x + 10
If the image of a linear function passes through (0,1) and is parallel to the line y = 1 / 2x-2, the analytic expression of the function is____ .
Y=1/2X+1
Since it is parallel to y = 1 / 2-2, the coefficient of X is 1 / 2
After (0.1) point,
So the following constant is 1
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