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a²+12ab+32b²
a²+12ab+32b²=（a+4b）（a+8b）
2a+ba2−2ab+b2÷4a2−b2ab2−a2b．
The original formula is 2A + B (a − b) 2 · AB (B − a) (2a − b) (2a + b) = - AB (a − b) (2a − b)
The second power of a-2ab + the second power of b-2a + B △ the second power of ab-the second power of a-the second power of B-the second power of B
The second power of a-2ab + the second power of b-2a + B △ the second power of ab-the second power of a-the second power of B-the second power of B
=(2a + b) / AB (B-A) (2a + b) (2a-b)
=(2a + b) x (2a + b) (2a-b) AB (B-A)
=1 / 2 [(B-A) (2a-b)]
RELATED INFORMATIONS
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