Block determinant ABCD = ad BC M = matrix ABCD proves that | m | = | ad-bc | does not give whether AD two are invertible

Block determinant ABCD = ad BC M = matrix ABCD proves that | m | = | ad-bc | does not give whether AD two are invertible


The conclusion is wrong!
A = [1 0; 0 1],B = [1 1; 1 1],C = [1 0; 0 0],C = [1 2; 3 4]
|M| = -3
|AD-BC| = -4



If the absolute value of ABCD / ABCD = 1, then (- the absolute value of ABCD / ABCD) + the absolute value of a / A + the absolute value of B / B + the absolute value of C


abcd/|abcd|=1
So ABCD > 0 has 2 negative numbers or 0 negative numbers
-|abcd|/abcd=-1
|a|/a+|b|/b+|c|/c+|d|/d=0 or 4
The original formula = - 1 or 3



ABCD are four rational numbers whose absolute values are 1234. Please write two formulas: make a + B + C + D = - 2
Formula 1:-------------
Formula 2:-------------
Can you write a formula such that a + B + C + D = - 1 () brackets are filled with "can" or "can't"


1-2+3-4=-2
4-1-3-2=-2
No
I wish you a happy study!