-A the absolute value of the opposite number is non negative, right? Must the absolute value of a be a positive number? -Must the absolute value of a be negative?

-A the absolute value of the opposite number is non negative, right? Must the absolute value of a be a positive number? -Must the absolute value of a be negative?

-A the absolute value of the opposite number is nonnegative, right? Yes
Must the absolute value of a be a positive number? No, it may be 0
-Must the absolute value of a be negative? No, the absolute value of any number cannot be negative

The absolute value of a + B + the absolute value of a-b - the absolute value of C-B
C is on the left of 0, a is on the right of 0, B is on the right of A

=a+b+b-a+b-c
=3b-c

It is known that a = MX & sup2; = 4x-7, B = - 2x & sup2; - 3x + 5N, if 3a-2b

Analysis
3A-2B
=3(mx²+4x-7)-2(-1/2x²-3x+5n)
=3mx²+12x-21-(-x²-6x+10n)
=3mx²+12x-21+x²+6x-10n
=(3m+1)x²+18x-10n-21

(3x + 5) (3-2x) = the square of AX + BX + C, a = () B = (), C = ()

(3x + 5) (3-2x) = - 6x-x + 15 = the square of AX + BX + C, so a = - 6, B = - 1, C = 15

Let (3x-2) square = ax square + BX + C
(1) Finding the value of C (2) finding the value of a + B + C

(3x-2) & sup2; expansion
=9x²-12x+4
=ax²+bx+c
So C = 4
When x = 1, a + B + C = ax & sup2; + BX + C = (3x-2) & sup2; = 1

If [3x's Square - 3x + 2] - [- X's square + 3x-3] = ax's Square - BX + C, then the value of ABC is

[3x's Square - 3x + 2] - [- X's square + 3x-3] = ax's Square - BX + C
The square of 3x - 3x + 2 + the square of X - 3x + 3 = the square of ax - BX + C
4X squared - 6x + 5 = ax squared - BX + C
therefore
a=4,b=6,c=5
So ABC = 120

2A - (3d-a) + 2B; (a + b) - (- B + C); 3 (x-2y) - 2 (3x-y) where x = 1y = 2 / 1

2A - (3d-a) + 2b2a-3d + A + 2B = 3A-3D + 2B (a + b) - (- B + C) = a + B + B-C = a + 2b-c3 (x-2y) - 2 (3x-y) 3x-6y-6x + 2Y = - 3x-4y when x = 1, y = 1 / 2 (half? Wrong title? I'll calculate by half) - 3x-4y = - 3 * 1-4 * 1 / 2 = - 3-2 = - 5

（x-2y=7 （1-3x=(y-1)/2
Solving equations

x-2y=7 （1）
1-3x=(y-1)/2
2（1-3x）=y-1
y+6x=3 (2)
(2) * 2 + (1) gain
13x=13
x=1
y=-3

If the sum of solutions X and y of the equations 3x + 2Y = a + 2,5x + y = a is 2, then the value of a is 2
emergency
A. - 2b.2c.0d. Any real number

(1) - (2) × 2
-7x=2-a
∴7x=a-2 (3)
(1) 5 - (2) × 3
7y=2a+10 (4)
(3) + (4) get
7x+7y=3a+8
7(x+y)=3a+8
∵x+y=2
∴3a+8=14
∴a=2

-a^3+2b^3-3ab+2=-（）=2-a^3- （）
I also want to ask this question: - A ^ 3 + 2B ^ 3-3ab + 2 = what is negative = 2-A ^ 3 - ()

Solution
-a³+2b³-3ab+2
=-(a³-2b³+3ab-2)
=2-a³-(3ab-2b³)