Calculate (- 3AB ^ 3C) ^ 2 (- A ^ 2b) ^ 3 -6a^2b(x-y)^3*1/3ab^2(y-x0 （-4x^2）（3x+1) (-3/2x^2y-3xy^2+2)-2xy (a+2b)(3a-4b) (2x-3y)^2(2x+3y)^2

Calculate (- 3AB ^ 3C) ^ 2 (- A ^ 2b) ^ 3 -6a^2b(x-y)^3*1/3ab^2(y-x0 （-4x^2）（3x+1) (-3/2x^2y-3xy^2+2)-2xy (a+2b)(3a-4b) (2x-3y)^2(2x+3y)^2

(-3ab^3c)^2(-a^2b)^3
=9a²b^6 c²×(-a^6b³)
=-9a^8 ²b^9 c²
-6a^2b(x-y)^3*1/3ab^2(y-x)
=6*1/3*a²b(x-y)^3*ab^2(x-y)
=2a³b³(x-y)⁴
（-4x^2）（3x+1)
=（-4x^2）*3x+（-4x^2）*1
=-12x³-4x²
(-3/2x^2y-3xy^2+2)-2xy
=-3/2x²y-3xy²+2-2xy
(I suspect that this question is copied wrong, otherwise it's too simple. Just remove the brackets.)
(a+2b)(3a-4b)
=3a²-4ab+6ab-8b²
=3a²+2ab-8b²
(2x-3y)^2(2x+3y)^2
=[(2x-3y)(2x+3y)]²
=(4x²-9y²)²
=16x⁴-72x²y²+81y⁴

|How to write it

The original formula = (1-2 / 1) + (2-1-3 / 1) + (3-1-4 / 1) + (4-1-5 / 1) + +(2011\1-2012\1)
=1-2\1+2\1-3\1+3\1-4\1+4\1-5\1+…… +2011\1-2012\1
=1-2012\1
=2012\2011

Given (5a + 3B + C) ^ 2 + | B + C-3 | + (2C + 4) ^ 2 = 0, find the solution of the equation (x + 3) / A + 2B (x-1) = 2C about X

The sum of two square numbers and an absolute value is equal to zero, they are all equal to zero
5A+3B+C=0
B+C-3=0
2C+4=0
The solution is C = 2
B=1
A=-1
Substituting into the equation: - (x + 3) + 2 (x-1) = 4
The solution is: x = 9

The third power of formula (a + b) = the third power of a + the square of 3A + the square of 3AB + the third power of B. use the formula to write the third power of (a-b), and the result is transformed into

(a-b) &³ is first transformed into [a + (- b)] &³ and then a formula can be set
(a-b)³
=[a+(-b)]³
=a³+3a²(-b)+3a(-b)²+(-b)³
=a³-3a²b+3ab²-b³

Given a + B = 4, ab = 3, find the value of 3A ^ 2B + 3AB ^ 2

By eliminating an unknown number from the known conditions, such as B = 3 / A and substituting it into a + B = 4, we can get a ^ 2-4a + 3 = 0, a = 1, B = 3 or a = 3, B = 1, and the required value is 36

The third power of a minus 3A minus the third power of B plus 3B

a^3-3a-b^3+3b
=(a^3-b^3)-3(a-b)
=(a-b)(a^2+ab+b^2)-3(a-b)
=(a-b)(a^2+ab+b^2-3)

-The second power of 3a is B + the second power of 12ab - 6ab

I don't know if this is the case. The title is a little unclear
（-3A）²+（12AB）²-6ab?
If so, it's equal to
9A²+144A²B²-6AB

If a ^ 2 + B ^ 2 + 2a-b = - 5 / 4, simplify (a-5b) (- a-5b) - (- A + 5b) ^ 2, and then evaluate

It is known that a ^ 2 + B ^ 2 + 2a-b = - 5 / 4, and it is sorted out that: (a + 1) ^ 2 + (B-1 / 2) ^ 2 = 0, so a + 1 = 0, B-1 / 2 = 0, and the solution is a = - 1, B = 1 / 2

The polynomial (- A-1) x to the 5th power - 1 / 3x to the B power + X-1 is a quartic trinomial about X, then the value of AB is ()
A.4 B.-4 C.5 D.-5

The formula is a quartic trinomial of X
So the fifth power of (- A-1) x = 0, B = 4
-a-1=0,b=4
a=-1,b=4
AB = - 4, choose B

Subtract the power of 4ab-3d from a person's polynomial to get the power of 2a-3ab to find the polynomial

Because a polynomial subtracts the power of 4ab-3d to get the power of 2a-3ab
So this polynomial is 2A & # 178; - 3AB + (4ab-3d & # 178;) = 2A & # 178; + ab-3d & # 178;