Write the numbers 1, 2, 3, 4 and 5 on the five cards, then mix them and arrange them into a line. The probability that the number can be divided by 2 or 5 is zero___ ．

Write the numbers 1, 2, 3, 4 and 5 on the five cards, then mix them and arrange them into a line. The probability that the number can be divided by 2 or 5 is zero___ ．

According to the meaning of the question, we know that this question is a classical probability type. All the events in the experiment are arranged in a row randomly by five cards, with a total of A55 = 120 results. The events that meet the conditions are arranged with the last three digits of 2, 4 and 5, with a total of c31a44 = 72. According to the probability formula of the classical probability type, we get P = 72120 = 35, so the answer is: 35

What's the minimum number of a number that can be divided by 4, 5 and 6?

The problem is to let you find the least common multiple of these three numbers
The answer is 60

A number is divided by 2,3,4,5,6, all of which are 1, and it is exactly divided by 7. What's the number
Write a function and explain it

The I times of the least common multiple of 23456 can be divided by 7
It is easy to know that the least common multiple of 23456 is 60
//////////////////////////////////////
#include
using namespace std;
int main()
{
int i;
for(i=1;i

A number is divided by 2, 3, 4, 5 and 6 respectively, and the remainder is 1. It is exactly divisible by 7. What is the number?

The least common multiple of 2,3,4,5,6 is 60
The number a satisfying that 2,3,4,5,6 are divided into 1 must satisfy a = 60K + 1
(k is a positive integer), and division by 7 must satisfy a = 7m (M is a positive integer)
The number is 301

What is a number that can be divided by 2.3.4.5.6 and have 1 / but divisible by 7?
efrgve

y=420×x－119 (x=1,2,3,…… ）If a number is divided by 2,3,4,5,6, that is, by 60, we first divide it by 60, and then subtract a number, then we will have 1, that is, y = 60 × X - (60 × Z-1). If this number can be divided by 7, we should divide both parts of this formula by 7, the first part (60 × x) and the most

What is the minimum number of a number that can be divided by 5 if you subtract 2 and 6 if you add 4

32

A number minus 3 can be divided by 6, plus 3 can be divided by 5, the minimum number is______ ．

A number minus 3 can be divided by 6: 9, 15, 21, 27 The numbers that can be divided by 5 are: 2, 7, 12, 17, 22, 27 The minimum number is 27

A number minus 3 can be divided by 4 and 7 at the same time. There are () such numbers,
The smallest number is ()

Countless as long as it's a multiple of 28 + 3
The smallest number is (31)

If you subtract the least common multiple of 4 and 6 from a number, you can only divide 1 and 7 to find the number

The least common multiple of 4 and 6 is 12
It can only divide 1 and 7. This number is 7
So this number is
12+7=19

Divisibility of numbers
If a can be divisible by C and B can be divisible by C, then the sum of a and B can be divisible by C?