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What is the probability that all three digits can be divided by 3 or 5?
There are 900 numbers from 100 to 999, among which 300 numbers can be divided by 3 (900 / 3 = 300, every three consecutive numbers have and only one can be divided by 3, the same below), 900 / 5 = 180 numbers can be divided by 5, 900 / 15 = 60 numbers can be divided by 15, so 300 + 180-60 = 420 numbers can be divided by 3 or 5 (among 300 numbers that can be divided by 3, there are also numbers that can be divided by 5, 180 numbers that can be divided by 5 also have numbers that can be divided by 3, So if you add the two, the number that can be divided by both 3 and 5 - that is, the number that can be divided by 15 - is calculated once more and subtracted). The probability is 420 / 900 = 7 / 15
From 100101102 If you take any integer from 200, the probability that the number can be divided by 4 is?
To tell you how to do it, you should multiply 4 by a certain number, starting from 4x25 = 100 to 4x50 = 200, so there are 26 numbers between 25 and 50, so the probability is 26 / 101
What is the probability that an integer between 0 and 100 can be divided by 7?
For integers within 100, there are 7,14,21,28,35,42,49,56,63,70,77,84,91,98 divisible by 7, totally 14
So the probability of being divisible by 7 is 14 / 101
Four students do the addition and subtraction exercise: write a six digit number at will, take its one digit number (not 0) to the left of the leftmost digit, get a new six digit number, and then add it with the original six digits. The answers they get are: 172536, 568741, 620708, 845267?
If the first five digits of the six digits are a and the single digit is B, then:
The sum of the two six digits is (10a + b) + (100000b + a) = 11a + 100001b = 11 (a + 9091b),
It's a multiple of 11,
172536=11*15685+1,
568741=11*51703+8,
620708=11*56428,
845267=11*76842+5,
So only 620708 may be correct
RELATED INFORMATIONS
- 1. The probability that any integer from 1 to 100 can be divided by 3 and 5 at the same time
- 2. Prove that 7 ^ (n) + 6n-1 can be divisible by 36
- 3. If you add 3 to a two digit number, you can divide it by 3, if you add 4, you can divide it by 4, if you add 5, you can divide it by 5
- 4. Try to explain that 523-521 can be divided by 120
- 5. Can 5 ^ 23-5 ^ 21 be divided by 120?
- 6. Characteristics divisible by 25,8,125,7,9,11,13
- 7. What are the characteristics of numbers divisible by 8 or 125
- 8. How many three digit numbers can be divided by two by four, five, six and three digital cards?
- 9. Using three different digital cards to place three digits, the probability of being divisible by three is 100%, the probability of being divisible by five is 1 / 3, and the probability of being divisible by two is 0 2/3
- 10. There are three cards with numbers 4, 5 and 0 written on them. Please use these three cards to form three digits. What numbers can be divided by 3 and 5 at the same time?
- 11. Write the numbers 1, 2, 3, 4 and 5 on the five cards, then mix them and arrange them in a row. The probability that the five digits can be divided by 5 or 2 is () A. 0.8B. 0.6C. 0.4D. 0.2
- 12. Write the numbers 1, 2, 3, 4 and 5 on the five cards, then mix them and arrange them into a line. The probability that the number can be divided by 2 or 5 is zero___ ．
- 13. (1) If one number is randomly selected from the 100 integers 1-100, the probability that the number can be divided by 8 is zero (2) If you toss an even coin twice at will, the probability that at least one coin will face up is zero (3) If you throw two dice at will, the probability that the sum of points is greater than 8 is 0 (4) At present, there are 7 playing cards, 2 of which are "King". After washing, randomly select 2 of them, and the probability of drawing at least 1 trump card is 0
- 14. The probability that the sum of 3 numbers can be divided by 3
- 15. From the four numbers of 2345, put them back three times, take any number each time, and find the probability that the product of the three numbers obtained can be divided by 10
- 16. If a six digit 2009 () can be divided by 105, what are the last two digits
- 17. Six digit 2003? Can be divided by 99, how many are its last two digits?
- 18. If six digit a2875b is divisible by 99, then two digit AB is ()
- 19. For example, the converse of the following proposition is a false proposition 1. If one digit of an integer is 5, then the integer can be divided by 5 2. If both angles are right angles, then the two angles are equal
- 20. In & nbsp; 1, 2, 3, 4 Take two numbers out of the 100 numbers, so that the sum of the two numbers can be divisible by 4, at most______ There are two different methods