Solve the equation and judge the root of the equation X2 - KX + (k - 2) = 0

Solve the equation and judge the root of the equation X2 - KX + (k - 2) = 0


∵ a = 1, B = - K, C = K-2, ∵ b2-4ac = k2-4 (K-2) = k2-4k + 8 = (K-2) 2 + 4 > 0, ∵ the equation has two unequal real roots