When m is an integer, the solution of the equation 12mx − 53 = 12 (x − 43) is a positive integer?

When m is an integer, the solution of the equation 12mx − 53 = 12 (x − 43) is a positive integer?

If we solve the equation 12mx − 53 = 12 (x − 43), remove the denominator, we get 3mx-10 = 3 (x-43), remove the bracket, we get 3mx-10 = 3x-4, transfer the term and merge the similar terms, we get x (m-1) = 2, the coefficient is 1, we get x = 2m − 1, ∵ the solution of the equation is a positive integer, ∵ x > 0 and is a positive integer, ∵ 2m − 1 > 0 and M is a positive integer, ∵ M-1 is a positive divisor of 2, that is, M-1 = 1 or 2, ∵ M = 2 or 3

It is known that the solutions of the equation x-m = 3x + 2M and the equation x + 1 = 3x-2 are opposite to each other

It's not hard. I just don't know if the molecule has brackets
According to the calculation without brackets
3x-6m=9x+4m
-6x=10m
x=-5m/3
x+2=6x-4
x=6/5
5m/3=6/5
25m=18
m=18/25

If x = 3 is the solution of the equation 4 / 3x + 2A + 1 = 0, then the value of 2a is

According to the meaning of the title,
∵ x = 3 is the solution of the univariate linear equation 4 / 3x + 2A + 1 = 0 about X
∴4/3×3+2A=－1
12+2A=－1
2A=－1－12
2A=－13