It is known that the solution of the equation 3x + 2m = 2x + 1 is the same as that of the equation 1 / 2x-3 (4-x) = 12. Find the value of (1): m (2): 200% of the algebraic value (M + 1 / 2) Algebraic value (M + 1 / 2) to the power of 2008 (4m-3) to the power of 2009

It is known that the solution of the equation 3x + 2m = 2x + 1 is the same as that of the equation 1 / 2x-3 (4-x) = 12. Find the value of (1): m (2): 200% of the algebraic value (M + 1 / 2) Algebraic value (M + 1 / 2) to the power of 2008 (4m-3) to the power of 2009


(1)3x+2m=2x+1 x=1-2m
1/2x-3(4-x)=-12 x=0
1-2m=0 m=1/2
(2)(m+1/2)^2008*(4m-3)^2009=(1/2+1/2)^2008*(4*1/2-3)^2009=1^2008*9(-1)^2009
=1*(-1)=-1



If the solution of the equation x-2m-3 = 3x = 7 is not less than or greater than 10, then there should be


The solution of equation x-2m-3 = 3x-7 is not less than and not more than 10
Then x = 10
Then 10-2m-3 = 3 * 10-7
m=-7



Is the solution of the equation x + 2m-3 = 3x + 7 between 2 and 10 whenever m is a value
Please


Transference
3x-x=2m-3-7
2x=2m-10
x=m-5
SO 2 ≤ m-5 ≤ 10
Add 5
7≤m≤15