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If ABCD is an unequal integer and ABCD = 49, find the value of a + B + C + D-1
∵abcd=49=7*7
Moreover, a, B, C and D are not equal to each other
A, B, C and D are an arrangement of - 1,1, - 7,7
∴a+b+c+d=0
∴a+b+c+d-1=-1
Four integers a, B, C, D are not equal to each other, and satisfy the condition ABCD = 49, find the value of formula a + B + C + D
∵ 49 = (- 1) × 1 × (- 7) × 7, ∵ these four numbers can only be - 1, 1, - 7, 7, ∵ a + B + C + D = - 1 + 1 + (- 7) + 7 = 0
If a, B, C and D are unequal integers and ABCD = 49, find the value of (a + B + C + D-1) ^ 2013
Is it an integer or an integer? If it is an integer, then ABCD is 1, - 1,7, - 7 respectively
A + B + C + D-1 = - 1, so the value is - 1
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