Please list out the physical quantities with positive and negative quantities, such as the positive and negative meanings of gravitational potential energy. Some of the positive and negative energies only represent the output, while others are the size?
In general, both positive and negative are relative, that is to say, one of them is taken as a reference. If it is higher than the other, it will be positive and lower than the other, it will be negative. For example, in order to determine the positive and negative of gravitational potential energy, it is necessary to determine the zero potential energy point. Similarly, the electric potential energy is the same. All potential energy is relative. There are also some physical quantities that are not potential energy, which have positive and negative, In fact, physical quantities can be divided into scalar vectors, and potential energy is the product of scalar and vector. For example, gravitational potential energy, mass (scalar) times height (ratio to zero potential point, vector). In this way, as long as we distinguish which are scalars and which are vectors, we can
Is the ratio of gravity to mass a physical quantity
thank you! O(∩_ ∩)O
Is the acceleration of gravity, G, in M · s ^ (- 2), read in meters per second
All physical quantities with both size and direction are called vectors. What's wrong
Road signs have size and direction
Is the formula v = V0 + at applicable to all motions? What does V stand for? What segment of acceleration does a refer to?
V is the velocity at time t (final velocity), V0 is the velocity at time 0 (initial velocity), and a is the acceleration from time 0 to time t
[(V0 + V0 + at) / 2] * t find the next step of detailed calculation? It is in the velocity formula
[(v0+v0+at)/2]*t
=[v0+at/2]*t
=v0t+at²/2
The formula VT ^ 2-v0 ^ 2 = 2As, when the final velocity is 0, why can we deduce V0 ^ 2 = 2As? Why not - V0 ^ 2 = 2As?
It's actually - V0 ^ 2 = 2As, where a is negative because it's slowing down - the transition from having speed to not having speed
When you say V0 ^ 2 = 2As, you should calculate the acceleration according to the positive, and the final figure is correct, that is, the direction should be described
Is the VT image a curve or a uniform motion? If the image is a curve, the average velocity = (VT + V0) / 2 can be used
The slope of the image is acceleration
So. If it's the whole line, the acceleration is changing
The average velocity can only be calculated by V = s / T
For any linear motion, we can use the formula v = V0 + VT / 2 to find the average velocity. Why is it wrong
No, this is only suitable for linear motion with constant acceleration and linear motion with constant velocity
In the acceleration formula and uniform variable speed motion formula, VT and
V0 is the initial velocity and VT is the final velocity
How to find the average velocity of the uniform variable speed linear motion with VT diagram, we need to use the formula
Average speed = (initial speed + final speed) divided by two