Find all the two digit numbers with exactly 10 divisors, and find the sum of all divisors of each number
Because 10 = 2 × 5 = 1 × 10, this number is 29 > 100, or the number decomposition formula can only be 3 × 24 = 48, or 5 × 24 = 80, it is two digits. Therefore, the two digits of exactly 10 divisors are only 48 and 80, and the sum of their divisors is: (1 + 3) (1 + 2 + 4 + 8 + 16) = 124; (1 + 5) (1 + 2 + 4 + 8 + 16) = 186