The order of the differential equation f [x, y, y ', (y' ') ^ 2, y ^ 9 = 0 is______ . Online solution, to process, thank you

The order of the differential equation f [x, y, y ', (y' ') ^ 2, y ^ 9 = 0 is______ . Online solution, to process, thank you


two



What order differential equation is XY '' '+ 2x ^ 2 * y' ^ 2 + x ^ 3Y = x ^ 4 + 1


The highest is Y "'
So it is a third order differential equation



Find the special solution of the differential equation y '+ 3Y = e ^ (- 2x) satisfying the initial condition y ∣ x = 0 = 2
Find the special solution of the differential equation y '+ 3Y = e ^ (- 2x) satisfying the initial condition y ∣ x = 0 = 5


There are introductions in general advanced mathematics textbooks



Let α be the second quadrant angle and | cos α / 2 | = - cos α / 2, then the value range of α / 2 is?


If α is the second quadrant angle, then α ∈ (2k π + π / 2, 2K π + π), so α / 2 ∈ (K π + π / 4, K π + π / 2), and because | cos α / 2 | = - cos α / 2, so α / 2 is in the second and third quadrants, so α / 2 ∈ (2k π + 5 π / 4, 2K π + 3 π / 2)



Using the pinch criterion to calculate limn tends to infinity (a ^ n + B ^ n) ^ 1 / N (a > 0, b > 0)


Hope to help you & nbsp; also hope to adopt~



If x is the fourth quadrant angle and | cosx / 2 | = - cosx / 2, then what quadrant angle is x / 2?


X is the fourth quadrant
2kπ-π/2



Using the pinch criterion to calculate limn [arctan ((n ^ 2) + 1) + arctan ((n ^ 2) + 2) +... + arctan ((n ^ 2) + n) - (n π / 2)] n tends to infinity


n^2[arctang((n^2)+1)-π/2]



Given that the point m (1-A, a + 2) is in the second quadrant, then the value range of a is______ .


∵ point m (1-A, a + 2) is in the second quadrant, ∵ 1 − a < 0A + 2 > 0, the solution is: a > 1



It is proved that limn tends to infinity, N / √ n & # 178; + n = 1





It is known that the straight line (3a-1) x + (2-A) Y-1 = 0, but the value range of a in the second quadrant is?


Because the line is not in the second quadrant, so
When x = 0, y < = 0
That is, 1 / (2-A) < = 0
A 〉 = 2
And when y = 0
X 〉=0
It is the same
a>=1/3
That is a > = 2