Composite function f (x) = x ^ 2Sin (1 / x) (x > 0) f (x) = 0 x

Composite function f (x) = x ^ 2Sin (1 / x) (x > 0) f (x) = 0 x


f'(0)=lim[x^2sin(1/x)-f(0)] /(x-0)
=lim[x^2sin(1/x)] /x
=limxsin(1/x)
=0
So it's differentiable and its derivative is zero
This problem needs to be done by definition
It only shows that the derivative is discontinuous at x = 0, but it can't show that the derivative doesn't exist



The sum of abscissa of all intersection points of image of function y = 11 − X and image of function y = 2Sin π x (- 2 ≤ x ≤ 4) is equal to ()
A. 2B. 4C. 6D. 8


The image of the function Y1 = 11 − x, y2 = 2Sin π X has a common center of symmetry (1,0). When 1 < x ≤ 4, Y1 < 0 and Y2 has an image of 1.5 cycles on (1,4), it is a decreasing function on (1,32) and (52,72); it is an increasing function on (32,52) and (72,4)



The sum of abscissa of all intersection points of the image of function y = 1 / X-1 and the image of function y = 2Sin π x (- 2 ≤ x ≤ 4) is? Hope the answer is clear and easy to understand, thank you
Well, it would be better to have a picture
The answer is 8, please.


Function y = 1 / (x-1) and function y = 2Sin π x (- 2 ≤ x ≤ 4) let t = X-1, then x = 1 + T, t ∈ [- 3,3], function y = 1 / (x-1) and function y = 2Sin π x, that is, y = 1 / T and y = 2Sin π (1 + T) = 2Sin (π + π T) = - 2Sin (π T), t ∈ [- 3,3], because y = 1 / T and y = - 2Sin π T are odd functions and definite