Given the function f (x) = 2Sin (2x + 30 °) + A + B + 1 (a > 0), when x is 0 to 90 °, the function value is [- 4, Please, big brother and big sister

Given the function f (x) = 2Sin (2x + 30 °) + A + B + 1 (a > 0), when x is 0 to 90 °, the function value is [- 4, Please, big brother and big sister


When x is 0 to 90 degrees, 2x + 30 is 30 to 210 degrees
2sin(2x+30°)∈[-1,2]
So,
The maximum and minimum difference of F (x) is only 2 - (- 1) = 3
It can't be in [- 4,2]. The title is wrong



The number of zeros of the function f (x) = 2x SiNx is______ &Nbsp; one


Because f '(x) = 2-cosx > 0 is constant on R, the function f (x) = 2x SiNx is monotonically increasing on R. and because f (0) = 0, the function f (x) = 2x SiNx has only one zero point 0



Let the distribution function of continuous random variable X be f (x). When x > = 0, f (x) = a + B times the power of (- X & sup2;) / 2 of E, where x is a continuous random variable


From the left continuity: at x = 0, f (0) = 0, bring in a + B = 0, f (x) is the distribution function, at infinity is equal to 1, bring in x = infinity, get a + b * 0 = 1, solve the equations: a = 1, B = - 1