The process of solving LIM (x → 0) Tan (2x ^ 2) / 1-cosx

The process of solving LIM (x → 0) Tan (2x ^ 2) / 1-cosx

lim(x→0)tan(2x^2)/1-cosx
=lim(x→0)tan(2x^2)/2sin²x/2
=4lim(x→0)[tan(2x^2)/2x²][(x/2)²/（2sin²x/2）]
=4

Given ｜ 3x + Y-2 | + (2x + 3Y + 1) ^ 2 = 0, find the value of X and y

Hello!
From the problem, we get 3x + Y-2 | = 0, (2x + 3Y + 1) ^ 2 = 0
So 3x + Y-2 = 0
2x+3y+1=0
The solution is x = 1
y=-1
Thank you~~

Solution multiplication: (1) 5 (X-8) = 3x (2) 9 (2x-3) - 2 = 5 (2x-1)
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1.5（X-8）＝3X
So: 5x-40 = 3x
So: 5x-3x = 40
So: 2x = 40
So: x = 20
2.9（2X-3）-2＝5（2X-1）
So: 18x-27-2 = 10x-5
So: 18x-10x = - 5 + 27 + 2
So: 8x = 24
So: x = 3