Find the value of X: (3x + 2) &# 178; = 16 1 / 2 (2x-1) &# 179; = - 4 | Math enthusiast | Mathematical art

Find the value of X: (3x + 2) &# 178; = 16 1 / 2 (2x-1) &# 179; = - 4

（3x+2）²=16
Square both sides
3x+2=±4
X = 2 / 3 or x = - 2
1/2（2x-1）³=-4
Divide both sides by 1 / 2
（2x-1）³=-8
If both sides open the cube at the same time:
2x-1=-2
x=-1/2

2X Cube - 3x + 2 / 3 x cube - 2x - 4 / 3 x cube + X-1, where x = - 0.5

2X Cube - 3x + 2 / 3 x cube - 2x - 4 / 3 x cube + X-1, where x = - 0.5
=4x³/3-4x-1
=4/3×(-1/2)³-4×(-1/2)-1
=4/3×(-1/8)+2-1
=-1/6+1
=5/6;
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Calculate; 2x ^ 3 times (- 3x) ^ 2

2X ^ 3 times (- 3x) ^ 2
=2x^3×9x^2
=18x^5

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