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How to solve 3x-5 times 2x of 3 = - 1
3x-5×2/3x=-1
If you multiply both sides by 3, you get the denominator
9x-10x=-3
-x=-3
x=3
3x+3-1/3x-1=2x+6-1/2x-1/2
Specific process
3x+3-1/3x-1=2x+6-1/2x-1/2
3x-2x+2-1/3x=11/2-1/2x
x+1/2x-1/3x=11/2-2
(6x+3x-2x)/6=7/2
(7x)/3=7
7x=7*3=21
x=3
Given that the function f (x) = x3-x decreases on (0, a) and increases on [a, + infinity), find the value of A
The process of calculation without derivation
f'(x)=3x^2-1
Let f '(x) = 0, then x = √ 3 / 3 and x = - √ 3 / 3 are two stationary points
Because it decreases on (0, a] and increases on [a, + infinity)
Then a = √ 3 / 3
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