An object with a mass of 1kg is subjected to two forces of 2n and 3N, Then the maximum and minimum accelerations of the object are -

An object with a mass of 1kg is subjected to two forces of 2n and 3N, Then the maximum and minimum accelerations of the object are -

The maximum force is 2 + 3 = 5N, so the maximum acceleration A1 = 5 / 1 = 5 m / S ^ 2
The minimum force is 3-2 = 1n, so the minimum acceleration A1 = 1 / 1 = 1 m / S ^ 2

If the three common forces are 5N, 3N and 7n, what is the minimum value of their resultant force

Assuming that the direction of the force of 7n is fixed and the direction of the force of 3N and 5N is rotated, when they are in the same direction, the resultant force is 8N, 8n7n, so the direction of the two forces can be adjusted to make their resultant force 7n, so that the resultant force of the three forces is 0, so the minimum resultant force is 0n

There are two forces, one is 3N and the other is 5N. Their resultant force may be?

Greater than or equal to 2n and less than or equal to 8N