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Three coplanar forces in different directions at the same level are applied to a 2kg body for uniform straight motion. We know that F 1 = 6N, F 2 = 7n, F 3 = 8N, F 1 and F 2, and the force F 1, the body plus a Three coplanar forces in different directions and at the same level are used to make a uniform straight motion on a 2kg body. If we know that F1 = 6N F2 = 7n F3 = 8N F1 and F2 and the force? F1, how much is the body plus a
The resultant force of F1 and F2 is the same as that of F3, but the direction is opposite. If F1 is removed, the acceleration = F1 / M = 3
The three forces of an object | F1 | = 10N, | F2 | = 8N and | F3 | = 6N are 30 ° north by East, 60 ° north by East and 30 ° north by west respectively
The object moves 10 meters in the direction of resultant force
Draw a picture to get the direction of the resultant force of F2 and F3 equal to F1
So the total force is f = 30 ° NBE, 20 n
So work w = FS = 20n * 10m = 200J
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