A force with definite direction f = 10N is decomposed into two forces. One component has definite direction and forms an angle of 30 ° with F, and the other component is 6N When it is decomposed A. With or without array solutions B. with two groups of solutions C. with unique solutions D. without solutions

A force with definite direction f = 10N is decomposed into two forces. One component has definite direction and forms an angle of 30 ° with F, and the other component is 6N When it is decomposed A. With or without array solutions B. with two groups of solutions C. with unique solutions D. without solutions


B. There are two sets of solutions



It is impossible to decompose a force of 8N into two components
It is impossible to decompose a force of 8N into two components ()
A. 1n and 10N
B. 10N and 10N
C. 10N and 15N
D. 15N and 20n
How to judge and calculate


The maximum of the resultant force of the two forces is the sum, and the minimum is the subtraction,
1 and 10, the minimum is 9, the maximum is 11, not the 8 you want
The other three 20
twenty-five
thirty-five
You can get 8



If a force F = 10N is decomposed into two components, the direction of one component is known to be 30 ° to F, and the magnitude of the other component is 6N, then ()
A. With or without array solution B. with two solutions C. with unique solution D. without solution


It is known that one component has a definite direction and is at an angle of 30 ° with F. the minimum value of the other component is fsin30 ° = 5N, and the size of the other component is greater than 5N and less than 10N. Therefore, there are two groups of solutions for the number of decomposition groups. As shown in the figure, B is correct, and a, C and D are wrong