A. The difference between the reciprocal of two natural numbers B is 1 / 182. Find the sum of two natural numbers a and B

A. The difference between the reciprocal of two natural numbers B is 1 / 182. Find the sum of two natural numbers a and B


A. B the difference between the reciprocal of two natural numbers is 1 / 182, then the difference between the two natural numbers is 1 and the product is 182
Then the two natural numbers are 13 and 14
So the sum of a and B is 13 + 14 = 27



The difference between the reciprocal of two natural numbers is 1 / 182. What is the sum of these two numbers?


182=13×14
∴1/182=1/13-1/14.
13×14=182.



The difference between the reciprocal of two adjacent natural numbers is 1 / 182. What is the sum of the two numbers?


Let the small number be x, then the large number be x + 1,
So 1 / x + 1 / (x + 1) = 1 / 182
That is x ^ 2 + x-182 = 0
The solution is x = 13
The two numbers are 13 and 14 respectively
And 27