Given that the product of two continuous positive even numbers equals 168, then the two even numbers are______ ．

Given that the product of two continuous positive even numbers equals 168, then the two even numbers are______ ．

Let the smaller even number be 2n, and the larger one be (2n + 2), (2n + 2) · 2n = 168, n = 6 or n = - 7 (rounding off). 2n = 12, 2n + 2 = 14. So the two even numbers are 12, 14. So the answer is: 12, 14

A = 2 × 3 × 5 × a, B = 2 × 3 × 7 × A. when a equals (), the greatest common divisor of a and B is 30. A is (), B is ()

A = 2 × 3 × 5 × a, B = 2 × 3 × 7 × A. when a is equal to (5), the greatest common divisor of a and B is 30. A is (150), B is (210)
30＝2×3×5

Decomposing natural numbers a and B into prime factors
We get a = 2x5x7xm, B = 3x5xm, if the least common multiple of a and B is 2730, then M
=（）

a=2x5x7xm,b=3x5xm,
Then the least common multiple of a and B must be 2 * 3 * 5 * 7 * m = 2730
The solution is m = 13