Solve the inequality | x + 3 | - | x-3 | > 3, please 3Q

Solve the inequality | x + 3 | - | x-3 | > 3, please 3Q

∣∣ x + 3 ∣ - ∣ x-3 ∣ > 3 = > ∣ x + 3 ∣ - ∣ x-3 ∣ > 3 (1) or ∣ x + 3 ∣ - ∣ x-3 ∣ 3, (1) becomes x + 3 - (x-3) > 3 holds (2) becomes x + 3 - (x-3) 3 holds when X3 does not hold (2) becomes - x-3 - (3-x) 3 holds when - 3x > 3 / 2 (2) becomes 3 + X - (3-x) so X3 / 2

The solution set of inequality (x + 3) (x + 1) < 0 is solved by 3Q

When x = - 3 or x = - 1, (x + 3) (x + 1) = 0 when x0, x + 1 > 0, (x + 3) (x + 1) > 0 when - 3

1÷3＋6﹦﹙4÷9﹚×﹙x＋6﹚ 3Q

1÷3＋6﹦﹙4÷9﹚×﹙x＋6﹚ 19/6=4/9x+8/3 4/9x=1/2 x=9/8